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3 years ago

HELP ME HELP ME HELP ME HELP ME

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

He made a profit of thirty dollars

MAXImum [283]3 years ago

6 0

Answer:

30 bucks!

Step-by-step explanation:

Hope this helped

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(3 x 10e-4) ( 3 x 10e7)

Rina8888 [55]

The answer is 9000..

5 0

3 years ago

Solve the equation using the quadratic formula. Enter each solution in simplest form.

sergeinik [125]

For this case we have the following quadratic equation:

$x ^ 2-4x + 23 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -4\\c = 23$

Substituting the values we have:

$x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}$

We have two roots:

$x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}$

ANswer:

$x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}$

6 0

3 years ago

Help pls will give 10 points

patriot [66]

Answer:

In the picture

Step-by-step explanation:

I hope that it's a clear explanation.

4 0

3 years ago

A test requires that you answer either part A or part B. Part A consists of 7 true-false questions, and part B consists of 5 mul

jeka94

Answer: 3253

Step-by-step explanation:

Given : A test requires that you answer either part A or part B.

Part A consists of 7 true-false questions.

i.e. there are 2 choices to answer each question.

Now, the number of ways to answer Part A : $2^7=128$ (1)

Part B consists of 5 multiple-choice questions with one correct answer out of five.

i.e. there are 5 choices to answer each question.

Now, the number of ways to answer Part B : $5^5=3125$ (2)

Now, the number of different ways to completed answer sheets are possible= $128+3125=3253$ [Add (1) and (2) ]

5 0

3 years ago

A particle sits on a smooth surface and is acted upon by a time dependent horizontal force, giving it an

garik1379 [7]

(a) By the fundamental theorem of calculus,

v(t) = v(0) + ∫₀ᵗ a(u) du

The particle starts at rest, so v(0) = 0. Computing the integral gives

v(t) = [2/3 u ³ + 2u ²]₀ᵗ = 2/3 t ³ + 2t ²

(b) Use the FTC again, but this time you want the distance, which means you need to integrate the speed of the particle, i.e. the absolute value of v(t). Fortunately, for t ≥ 0, we have v(t) ≥ 0 and |v(t) | = v(t), so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of

∫₀⁸ v(u) du = ∫₀⁸ (2/3 u ³ + 2u ²) du = [1/6 u ⁴ + 2/3 u ³]₀⁸ = 1024

7 0

3 years ago