Question

Sonya found that x = StartFraction negative 4 Over 3 EndFraction is one solution of (6x + 4)2 = . The other solution is x = .

Answer 1

The other solution is x = 0.

Step-by-step explanation:

Let the value of (?) is C.

It the given equation is $(6x+4)^{2}$ = C .

It can be written as $(6x+4)^{2} - C$

Since x = $\frac{-4}{3}$ is the solution of the given equation, therefore  will satisfies the given equation.

Put  x = $\frac{-4}{3}$

$( 6 (\frac{-4}{3}) + 4 )^{2} - C = 0$

$( -8 + 4 )^{2}$ - C = 0

$- 4^{2}$ - C = 0

C = 16

The given equation become

$(6x+4)^{2} + 16 = 0$

$6x + 4 = 4$

6x = 0

$6x + 4 = -4$

x = $\frac{-4}{3}$

The other solution is x = 0.

Answer 2

Answer:

One solution of (6x + 4)^2 = 16

The other solution is x =  0