Answer:
Null hypothesis: 
Alternative hypothesis: 
The statistic to check the hypothesis is given by:
And is distributed with n-2 degrees of freedom
And the statistic to check the significance of a coeffcient in a regression is given by:
For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:
Always
Step-by-step explanation:
In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:
Null hypothesis:
Alternative hypothesis:
The statistic to check the hypothesis is given by:
And is distributed with n-2 degrees of freedom
And the statistic to check the significance of a coeffcient in a regression is given by:
For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:
Always
Answer:
b. 58%
Step-by-step explanation:
Calculate the area of the entire rectangle using the formula A = lw.
The lowercase "L" is for length.
"w" is for width.
The lighter square is 10 units long by 5 inches wide.
A = lw
A = (10 in)(5 in) Multiply
A = 50 in²
Calculate the area for the shaded rectangle, 7 inches by 3 inches.
A = lw
A = (7 in)(3 in) Multiply
A = 21 in²
Calculate the area for the non-shaded region by subtracting the shaded area from the total area.
50 in² - 21 in² = 29 in²
The chance that a point in the large rectangle will NOT be in the shaded region is 29/50.
Convert this fraction to decimal form by using a calculator. Divide the top number by the bottom number.
29/50 = 0.58
0.58 is in decimal form. To convert it to a percentage, multiply the number by 100.
0.58 = 58%
Therefore the probability that a point chosen inside the large rectangle is not in the shaded region is 58%.
Answer:
DA/dt = 75.27 cm²
Step-by-step explanation:
Cube Volume = V(c) = 683 cm³
DV(c) /dt = 824 cm³
V(c,x) = x³
Then
DV(c,x)/ dt = 3x² Dx/dt
( DV(c,x)/ dt )/ 3x² = Dx/dt (1)
Now as V(c,x) = x³ when V(c,x) = 683 cm³ x = ∛683
x = 8.806 ( from excel)
And by subtitution of this value in equation (1)
Dx/dt = ( DV(c,x)/ dt )/ 3x² ⇒ Dx/dt = 824 / 3*x²
Dx/dt = 824 /3*77.55
Dx/dt = 824/232,64
Dx/dt = 3,542
Then we got Dx/dt where x is cube edge. The area of the face is x² then
the rate of change of the suface area is
DA/dt = ( Dx/dt )²*6 ( 6 faces of a cube)
DA/dt = (3.542)²*6
DA/dt = 75.27 cm²
Answer:
I cannot see the question clearly. But I know how to do .
Distribute
2z-1=z+8-2z
add like terms
2z-1=-z+8
add z to both sides
3z-1=8
add 1 to both sides
3z=9
divide both sides by 3
z=3
