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Ahat [919]
4 years ago
10

How do you do question 4?

Mathematics
1 answer:
boyakko [2]4 years ago
8 0
The answer of ur question is A
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CAN SONEONE PLEASE HELP ME WITH MY MATH PLEASEEEE!!!!!​
Marina86 [1]

Answer:

√190

Step-by-step explanation:

In the figure , there are 2 right angled triangles with a common perpendicular & both the triangles combine to form a new right angled triangle.

Let the triangle with 9 as base be T¹ & Let the triangle with base 10 be T². Let the triangle formed by T¹ & T² be T³.

In T² ,

Hypotenuse = y

Base = 10

According to Pythagorean Theorem ,

(Hypotenuse)² = (Base)² + (Perpendicular)²

Hence, (Perpendicular)² = y^2 - 10^2 = y^2 - 100

In T¹ ,

Perpendicular = \sqrt{y^2 - 100}   (∵ Both T¹ & T² have common perpendicular)

⇒(Perpendicular)² = y^2 - 100

Base = 9

⇒ (Base)² = 9²

Hypotenuse =

Using Pythagorean Theorem ,

(Hypotenuse)² = (Perpendicular)² + (Base)²

⇒ (Hypotenuse)² = y^2 - 100 + 9^2 .............................................eqn.2

Now in T³ ,

Base = y

⇒ (Base)² = y²

Perpendicular = \sqrt{(y^2 - 100) + 9^2} (∵Perpendicular of T³ = Hypotenuse of T²)

⇒ (Perpendicular)² = (\sqrt{(y^2 - 100) + 9^2})^2= (y^2 - 100) + 81 = y^2 - 19

Hypotenuse = 9 + 10 = 19

Using Pythagorean Theorem ,

(Hypotenuse)² = (Perpendicular)² + (Base)²

=> 19^2 = y^2 - 19 + y^2\\\\=> 2y^2 = 19^2 + 19 = 19(19 + 1) = 19*20\\\\=> y^2 = \frac{19*20}{2} = 19*10 = 190\\ \\=> y =\sqrt{190}

3 0
3 years ago
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