Question

Find the magnitude of the vector with (8,-6) and write the vector as the sum of unit vectors.

Answer 1

Answer:

The magnitude is 10 units.

Step-by-step explanation:

we have to find the magnitude of vector and also vector as the sum of unit vectors.

The magnitude of a vector is simply the Pythagorean Theorem

$\sqrt{a^2+b^2} = ||(a,b)||$

a=8, b=-6

$\sqrt{8^2+(-6)^2} = ||(8,-6)||$

$magnitude = \sqrt{64+36}=\sqrt{100}=10 units$

The unit vector is

$=$

And in unit vector form, we have:

$=8\hat{i}-6\hat{j}$

Answer 2

The magnitude of a vector is simply the Pythagorean Theorem!
$\sqrt{a^2+b^2} = magnitude$
a=8, b=-6

$\sqrt{8^2+(-6)^2} = magnitude$
magnitude = 10


Unit vector: (8/10, -6/10).
Divide by 10!(magnitude)