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Answer:
8 seconds.
Step-by-step explanation:
To solve this question, we need to find the time, , when
, that is, when the height of the object above the ground is 0 feet.
Substituting feet per second and
gives the quadratic:
Since 128 is divisible by 16, it can be reduced to .
We must now solve for .
We can easily see that one answer to the equation is 0,
(we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.
The second answer, is also easy to see by inspection:
.
Therefore the object lands 8 seconds after it is thrown.
Answer:
The answer is below
Step-by-step explanation:
The co-vertices of an ellipse are the endpoints of the minor axis. The equation for an ellipse is given by:
Where (h, k) is the center of the ellipse, (h, k±b) is the co-vertices, (h ± a, k) is the vertices, (h ± c, k) is the foci and c² = a² - b²
Since the center is the origin, hence (h, k) = (0, 0). i.e h = 0, k = 0.
Foci = (h ± c, k) = (± c, 0) = (±3, 0). c = 3
co-vertices = (h, k±b) = (0, ±b) = (0, ±4). b = 4
c² = a² - b²
a² = c² + b²
a² = 3² + 4² = 25
a = 5
Therefore the equation of the ellipse is: