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3 years ago

Write three numbers that are greater than 543,000 but less than 544,000

1 answer:

4 0

543,100
543,400
543,642
543,636
543,367
543,745
All you have to do is change the last 3 digits to any number, while keeping the first 3(543) the same.

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For an angle (theta) with the point (5, -12) on its terminating side, what is the value of cosine?

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we are given

(x,y)=(5,-12)

so, x=5 and y=-12

now, we can find r

$r=\sqrt{x^2+y^2}$

$r=\sqrt{5^2+(-12)^2}$

$r=13$

now, we can find cos

$cos(\theta)=\frac{x}{r}$

so, we get

$cos(\theta)=\frac{5}{13}$ ...........Answer

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Answer:

Step-by-step explanation:

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3 years ago

if p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? a: 5(x – 1) – x2 – 1 b: (5x – 1) – (x2 – 1) c: (

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The diameter of circles A,C and E are 32 cm, 24cm and 14 cm respectively

Karolina [17]

Answer:

AG = 4

AH = 21

EC = 12

CH = 5

HE = 7

Step-by-step explanation:

The complete question is

The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.

Which of the following statements are true? Select all that apply.

•AG = 4

•GC = 10

•AH = 21

•EC = 12

•EH = 5

•CH = 5

•HE = 7

The picture of the question in the attached figure

Verify each statement

1) AG = 4

we know that

$AG=AC-GC$

$AC=32\2=16\ cm$ ----> radius of circle A

$GC=24/2=12\ cm$ ----> radius of circle C

substitute

$AG=16-12=4\ cm$

therefore

The statement is true

2) GC = 10

we know that

$GC=24/2=12\ cm$ ----> radius of circle C

therefore

The statement is false

3) AH = 21

we know that

$AH=AC+CH$

we have

$AC=16\ cm$ ----> radius of circle A

$CH=CE-HE$

$CE=12\ cm$ ----> radius of circle C

$HE=14/2=7\ cm$ ----> radius of circle E

$CH=12-7=5\ cm$

$AH=16+5=21\ cm$

therefore

The statement is true

4) EC = 12

we know that

$EC=24/2=12\ cm$ ----> radius of circle C

therefore

The statement is true

5) EH = 5

we know that

$EH=14/2=7\ cm$ ----> radius of circle E

therefore

The statement is false

6) CH = 5

we know that

$CH=CE-HE$

$CE=12\ cm$ ----> radius of circle C

$HE=14/2=7\ cm$ ----> radius of circle E

$CH=12-7=5\ cm$

therefore

The statement is true

7) HE = 7

we know that

$HE=14/2=7\ cm$ ----> radius of circle E

therefore

The statement is true

3 0

3 years ago