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Levart [38]
3 years ago
13

Which statement describes the graph of function g compared to function f?

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0

Answer: OPTION B.

Step-by-step explanation:

Below are some transformations for a function f(x):

1. If f(ax) and a>1, the function is compressed horizontally by a factor of \frac{1}{a}.

2. If f(ax)  and 0, the function is stretched horizontally by a factor of \frac{1}{a}.

3. If bf(x) and 0, the function is compressed vertically by a factor of "b".

4. If bf(x)  and b>1, the function is stretched vertically by a factor of "b".

In this  case you have the function f(x):

f(x)=6^{x-2}

And the function g(x):

g(x)=0.4(6)^{x-2}

So, you can identify that:

g(x)=bf(x) and  0

Therefore, the graph of the function g(x) is a vertical compression of the graph of function f(x).

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Let's notice, the focus is at (5,0) and the directrix at x = -5.

keep in mind that there's a distance "p" from the vertex to either of those fellows, therefore, if the focus is at 5,0 and the directrix x = -5, the vertex is half-way between them, check the picture below.

notice the distance "p" there, now, is a horizontal parabola, opening to the right, meaning the value for "p" is positive, or just 5, thus

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})}
\\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}})
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=0\\
k=0\\
p=5
\end{cases}\implies (y-0)^2=4(5)(x-0)\implies y^2=20x
\\\\\\
\cfrac{y^2}{20}=x\implies \cfrac{1}{20}y^2=x

8 0
3 years ago
Rylee read 36 pages of a book before putting
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Answer:

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Step-by-step explanation:

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The inequality expressing a sum greater than 480 is ...

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