Answer:
yes
Step-by-step explanation:
To determine if the point is a solution, substitute the coordinates into the left side of the inequality, evaluate and compare with right side.
- 8(3) - 2(2) = - 24 - 4 = - 28 < 6
Thus (3, 2) is a solution
First, I would multiply the last two fractions because they're smaller and easier to work with:
Now that we've simplified it, we could multiply these terms and simplify. An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:
We can now multiply these terms:
The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>
Answer:
sorry flood so do hell no DC cough
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
h=2A/a+b
Step-by-step explanation:
Distribute the terms
Divide by two
Isolate h
That would be the steps
