3 years ago

Write a polynomial function in standard form with zeros at 0,1,and 2

1 answer:

8 0

I'm going to build it from the bottom up:
(x+0)(x-1)(x-2)=y
x(x-1)(x-2)=y
x[(x^2) -3x+2]=y
(x^3) -(3x^2)+2x=y
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3 more than 6 times a number

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assuming you're looking for an expression, it would be written as "6x+3".

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If both the length and width of a rectangle are doubled, how is the area of the rectangle changed?

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2 years ago

Simplify completely X2 + 4x - 45 ÷ x2 + 10x + 9 and find the restrictions on the variable

svetoff [14.1K]

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Step-by-step explanation:

Factor the numerator:

(x+9)(x-5)

Factor the denominator:

(x+1)(x+9)

So you have

(x+9)(x-5)/(x+1)(x+9); see that you can cross out the (x+9) in both the numerator and denominator?

You're left with (x-5)/(x+1)

The only number that is restricted is -1, because that would make the denominator zero, which is a no no!!

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