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Otrada [13]
2 years ago
11

2.

Mathematics
1 answer:
dimulka [17.4K]2 years ago
4 0

Answer:

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What equivalent of 4:25
Lady_Fox [76]

Answer: 16 percent

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Suppose y varies inversely with x, and y = a when x = a 2. What inverse variation equation relates x and y ?
Sphinxa [80]

The variation equation is xy = a^3

<h3>How to determine the equation?</h3>

An inverse variation is represented as:

xy = k

Where k is the constant of variation

When y = a and x =a^2, we have:

k = a * a^2

Evaluate

k = a^3

Substitute k = a^3 in xy = k

xy = a^3

Hence, the equation is xy = a^3

Read more about variation at:

brainly.com/question/6499629

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6 0
2 years ago
Identify the dollar amount due on a sample of 49 credit cardsModeMedianmean
Anvisha [2.4K]

Given:

Identify the dollar amount due on a sample of 49 credit cards.

The amount due on the next payment is any one of the averages that mode,median or mean can be used.

5 0
1 year ago
Pls help<br>Solve 2/3x- 1/5&gt;1<br> ​
Juli2301 [7.4K]

Answer:

x > 9/5

Step-by-step explanation:

Step 1: Write inequality

2/3x - 1/5 > 1

Step 2: Solve for <em>x</em>

  1. Add 1/5 to both sides: 2/3x > 6/5
  2. Divide both sides by 2/3: x > 9/5

Here we see that any <em>x</em> value greater than 9/5 will work.

7 0
3 years ago
What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,...
navik [9.2K]

Answer:

The nth term rule of the quadratic sequence is 2n^{2} +5n-3.

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by =  an^{2}+bn+c

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a  =  \dfrac{4}{2} = 2

SO, the first term of the nth term rule equation is an^{2} = 2n^{2}.

Now, in the term 2n^{2}, put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then 2n^{2} = 2 \times (1)^{2} = 2

If n = 2, then 2n^{2} = 2 \times (2)^{2} = 8

If n = 3, then 2n^{2} = 2 \times (3)^{2} = 18

If n = 4, then 2n^{2} = 2 \times (4)^{2} = 32

If n = 5, then 2n^{2} = 2 \times (5)^{2} = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is 2n^{2} +5n-3.

7 0
3 years ago
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