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Nastasia [14]
3 years ago
11

Como eu divido 3/4 por 20?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
3 0
Você pode, mas não receberá um bom número limpo. Eu recomendo que você faça divisão longa
You might be interested in
You are planning to make an open rectangular box from a 25​-in.-by-49​-in. piece of cardboard by cutting congruent squares from
Darya [45]

Answer:

The dimensions of the box are 38.48 x 14.48 x 5.26 in.

Step-by-step explanation:

We will have a piece of cardboard with squares of side x cut from the corners to make a open box.

The volume of the box can be written as:

V=A\cdot B\cdot x\\\\V=(49-2x)\cdot (25-2x)\cdot x\\\\V=x\cdot (4x^2-2x*(49+25)+49*25)\\\\V=4x^3-148x^2+1225x

To calculate the maximum volume, we derive and equal to zero

dV/dx=12x^2-296x+1225=0

We apply the quadratic equation to know the roots of the equation

x=\frac{-b\pm\sqrt{b^24ac}}{2a}\\\\x=\frac{296\pm\sqrt{296^2-4*12*1225}}{2*12}  =\frac{296\pm\sqrt{87616-58800}}{24}= \frac{296\pm\sqrt{28816}}{24}\\\\x=\frac{296\pm169.75}{24}= 12.333\pm7.073\\\\\\x_1=12.333+7.073=19.406\\\\x_2=12.333-7.073=5.26

The first solution is physically impossible, as the side that is cut would be bigger than 25.

So the real solution is for x=5.26 in.

Then, the dimensions of the box are:

A=49-2x=49-2*5.26=49-10.52=38.48\\\\B=25-2x=25-10.52=14.48

8 0
3 years ago
M - 1 = 2 what do I need to do to solve.
andreyandreev [35.5K]

In order to solve this, start by adding 1 to both sides of the equation.


m-1=2

+1 +1

-----------

m=3


The solution to your equation is 3.


You can also check to see if this is true by replacing m with 3.

m-1=2

3-1=2

7 0
3 years ago
Suppose you are climbing a hill whose shape is given by the equation z = 1400 − 0.005x2 − 0.01y2, where x, y, and z are measured
Anarel [89]
Answer: You start to ascend

Explanation:

Since you are walking due south and the positive y-axis points north, the y-coordinate decreases.

Let 

y' = y-coordinate after walking due south
z' = z-coordinate (or the height) after walking due south

So, the point where you stand after walking due south has a coordinate of (100, y', z'). Moreover,

z' = 1,400 - 0.05(100)^2 - 0.01(y')^2
\\ \boxed{z' = 1350 - 0.01(y')^2}

Since the y-coordinate decreases after walking due south and z' = 1350 - 0.01(y')^2,

y'  \leq 120\\ \Rightarrow (y')^2 \leq 120^2 = 14,400\\ \Rightarrow -0.01(y')^2 \geq -0.01(14,400) = -144\\ \Rightarrow z' = 1,350 - 0.01(y')^2 \geq 1,350 - 0.01(14,400) = 1,206\\ \Rightarrow \boxed{z' \geq 1,206}

So, the height after walking due south exceeds 1,206 meters, which is the previous height before walking due south. Therefore, if you walk due south from point with coordinates (100, 120, 1206), you are ascending.
5 0
3 years ago
What is the value of y¹ when y = 5 and x - 10?​
Mrrafil [7]

Answer:

5

Step-by-step explanation:

y^1 = 5^1 (y = 5)

Anything raised to the power of 1 is just itself.

So, 5^1 = 5

8 0
2 years ago
6 more than the difference of b and 5
kirza4 [7]
The answer would be b-5+6
8 0
3 years ago
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