<span>The simplest method to do this is with the vector dot
product. Let the vector A = <9i + 5j> with magnitude √106 be the base
diagonal, and B = <5j + 3k> be the diagonal vector on the side, with
magnitude √34. Then cos θ = (A dot B) divided by the product of the magnitudes.
A dot B =30, so
cos θ = 30 / √(34 x 106)</span>
<span> = 0.4997 ==></span>
<span> θ = 49.19° is the
answer</span>
Answer:
A. segment PS ≅ segment QR
Step-by-step explanation:
Given that the quadrilateral PQRS is a rectangle then;
- The diagonals are PR and SQ
- Point of intersection of diagonals is T
- Segment PS≅ Segment QR
- ∠PSQ≅ ∠SQR
- segment SR≅ segment PQ
Answer: C
Step-by-step explanation:
8 * 8 = 64
x = 8
C = 180 - A - B
And
C = 180 - (A+B)
Hope I can help you :)
Brainliest answer :)) ?
Answer:
a
Step-by-step explanation:
