<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean and a standard deviation . For a value x we compute the z-score as , so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
Answer:
x=5
Step-by-step explanation:
That is a right angle, so 18x=90. To find x, you have to divide 90 by 18, which gives you 5.
Answer:
x = 115° , y = 65° , z = 115°
Step-by-step explanation:
The figure is a parallelogram.
Consecutive angles are supplementary ( sum to 180° ) , then
x + 65° = 180 ( subtract 65° from both sides )
x = 115°
Opposite angles are congruent , then
y = 65°
z = x = 115°