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max2010maxim [7]
3 years ago
10

Two lines and a ray intersect at a

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

m<DAE = 80°

Step-by-step explanation:

Given that m<CAB = 110°,

m<DAE = (x + 4)°,

m<EAF = 30°,

m<EAF + m<DAE = m<DAF (angle addition postulate)

30° + (x + 4)° = m<DAF (substitution)

(34 + x)° = m<DAF

<DAF and <CAB are vertically opposite angles. Vertically opposite angles are said to be congruent. Therefore:

m<DAF = m<CAB

(34 + x)° = 110° (substitution)

The equation above can be used to solve for x as follows:

34 + x = 110

x = 110 - 34 (Subtracting 34 from both sides)

x = 76

m<DAE = (x + 4)°

Plug in 76, to replace x

m<DAE = 76 + 4

m<DAE = 80°

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(I went too far in my explanation; I'm not going to erase it because I think it is important to have an example on solving these)

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