Answer:
1) 17.5
2)43.96
3)20
4) 15.7
5)25
Step-by-step explanation:
ohhhh yes
Given:
Equations using properties.
To find:
The equation which use the inverse property of multiplication.
Solution:
<u>Inverse property of multiplication:</u>
<em>The product of any number and its reciprocal is always 1.</em>
Let us select the option which uses inverse property of multiplication.
Option A: 
Inverse of 
is 
. Their product is 1.
This equation uses the inverse property of multiplication.
Option B: 
Inverse of 
is 
So, it is not true equation.
Option C: 
Inverse of 
is 
.
So, it is not true equation.
Option D: ![\left[7 \cdot\left(\frac{5}{7}-\frac{4}{7}\right)\right]+8=9](https://tex.z-dn.net/?f=%5Cleft%5B7%20%5Ccdot%5Cleft%28%5Cfrac%7B5%7D%7B7%7D-%5Cfrac%7B4%7D%7B7%7D%5Cright%29%5Cright%5D%2B8%3D9)
Here also inverse property is not used.
So, it is not true equation.
Hence the equation use the inverse property of multiplication is
.
3.Slope: 10 Y int: 5
4. Slope: 5 Y int: 10
6.Slope: 1/3 Y int: 3.5
7.Slope: 4/3 Y int: -1
8.Slope: 2/-4 Y int: -1
The way you do this is the Y int is where the line crosses through the y-axis. Finding the slope is finding the rise over run (y/x). It's easy to find when you know how to.
Use 4. as an example. Start where at (-3,-5) or (-2,0). Each 'rise' up 5 and 'runs' one block over, giving you the slope of 5/1 or 5 simplified.
7 is harder, but start at (-3,-5). It 'rises' up 4, then 'runs' 3, also giving you the y int, as it crosses the axis. As the rise is 4 and run is 3, it creates the slope 4/3.
Z-scores (left tail) of a given variable X are calculated by
Z(x)=(x-mean)/standard deviation.
For Mary:
Zm(124)=(124-110)/8=14/8=1.75
For Carrie:
Zc(289)=(289-250)/20=39/20=1.95
therefore
Zc>Zm
On Monday, Nora read ¼ of the book, therefore she is left
with ¾ of the original book.
Then on Tuesday, she read 2/5 of what was left on Monday
therefore she is left with 3/5 of ¾ of the original book. This is equal to:
(3/5) (3/4) = 9/20
<span>She still needs to read 9/20 of the book or 0.45 or 45% of
the book.</span>
