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seraphim [82]
3 years ago
15

Help!!! How do you solve problems like these anyway? Answers would help too

Mathematics
1 answer:
Zanzabum3 years ago
4 0

3.Slope: 10 Y int: 5

4. Slope: 5 Y int: 10

6.Slope: 1/3 Y int: 3.5

7.Slope: 4/3 Y int: -1

8.Slope: 2/-4 Y int: -1

The way you do this is the Y int is where the line crosses through the y-axis. Finding the slope is finding the rise over run (y/x). It's easy to find when you know how to.

Use 4. as an example. Start where at (-3,-5) or (-2,0). Each 'rise' up 5 and 'runs' one block over, giving you the slope of 5/1 or 5 simplified.

7 is harder, but start at (-3,-5). It 'rises' up 4, then 'runs' 3, also giving you the y int, as it crosses the axis. As the rise is 4 and run is 3, it creates the slope 4/3.

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4 years ago
An equation is shown below:
GREYUIT [131]
Part A:
    firs multiply 9 to 3x and minus 16, after that subtract 15 from -144, then add both side to 129, then subtract 6x from both side,  at the end divide bothe side to 21, the answer is 5. 
  9(3x-16)+15=6x-24
    27x-144+15 = 6x-24
     27x-129 = 6x-24
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7 0
4 years ago
Read 2 more answers
What is f(x) = 0,5 (x-3)( x-5) in general form??​
Citrus2011 [14]

Answer:

f(x)=0.5x^2-4x+7.5

Step-by-step explanation:

The general form of a quadratic function is:

y=ax^2+bx+c

We'll find the general form of the function:

f(x)=0.5(x-3)(x-5)

Multiplying the expressions in parentheses:

f(x)=0.5(x^2-5x-3x+15)

Simplifying:

f(x)=0.5(x^2-8x+15)

Operating:

\mathbf{f(x)=0.5x^2-4x+7.5}

4 0
3 years ago
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