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ira [324]
2 years ago
10

Nora read 1/4 of a book on monday and 2/5 on tuesday. what fraction of the book does she have left to read?

Mathematics
1 answer:
taurus [48]2 years ago
7 0

On Monday, Nora read ¼ of the book, therefore she is left with ¾ of the original book.

Then on Tuesday, she read 2/5 of what was left on Monday therefore she is left with 3/5 of ¾ of the original book. This is equal to:

(3/5) (3/4) = 9/20

<span>She still needs to read 9/20 of the book or 0.45 or 45% of the book.</span>

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Convert the following into metres.<br> A- 22cm<br> B- 180km<br> C-300mm
Alecsey [184]

<em>A) 22cm</em>

<em>(</em><em> </em><em>divide the length value by 100</em><em>)</em>

<em>2</em><em>2</em><em>/</em><em>1</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>

<em><u>=</u></em><em><u>0.22m</u></em>

<em>B</em><em>)</em><em> </em><em>180km</em>

<em>(</em><em> </em><em>multiply the length value by </em><em>1000</em><em>)</em>

<em>1</em><em>8</em><em>0</em><em>×</em><em>+</em><em>1</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>

<em><u>=</u></em><em><u>180000m</u></em>

<em>C</em><em>)</em><em> </em><em>300mm</em>

<em>(</em><em> </em><em>divide the length value by 1000</em><em>)</em>

<em>3</em><em>0</em><em>0</em><em>/</em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>which</em><em> </em><em>gives</em><em> </em><em>you</em><em>:</em>

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<em> </em>

4 0
2 years ago
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Solve for a....please!!!!!!
Readme [11.4K]

Multiply both sides by d.

dm=a+64d

Flip the equation.

a+64d=dm

Add -64d to both sides.

a=dm−64d

Answer:

<u>a=dm−64d</u>

6 0
3 years ago
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A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack
adelina 88 [10]

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

<u><em>Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."</em></u>

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

<u><em>Option B: "The value 70 is an outlier in the trail mix data.</em></u>"

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

<em><u>Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."</u></em>

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

<em><u>Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."</u></em>

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

6 0
3 years ago
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Lynna [10]
(a) 50%
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Explanation:

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(b)
No. of juniors that do not have a job = 34
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% of juniors that do not have a job = 34/200 x 100% = 17/100 x 100% = 17%
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B>$500? If this is an equality, but it is true
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3 years ago
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