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Zarrin [17]
3 years ago
8

A vaccine to prevent severe rotavirus gastroenteritis (diarrhea) was given to African children within the first year of life as

part of a drug study. The study reported that of the 3298 children randomly assigned the vaccine, 63 got the virus. Of the 1641 children randomly assigned the placebo, 80 got the virus. (Source: Madhi et al., Effect of human rotavirus vaccine on severe diarrhea in African infants, New England Journal of Medicine, vol.362:289-298, January 28, 2010) a. Find the sample percentage of children who caught the virus in each group. Is the ample percent lower for the vaccine group, as investigators hoped? b. Determine whether the vaccine is effective in reducing the chance of catching the virus. Steps l and 2 of the hypothesis-testing procedure are given. Complete the question by doing the rest of the steps. Step 1: H_0: p_v = p_p (p_v is the proportion of children that got the virus among those who took the vaccine, and p_p is the proportion of children that got the virus among those who took the placebo.) H_0: p_v < p_p Step 2: Although we don't have a random sample, we do have random allocation to groups. p = 63 + 80/3298 + 1641 = 143/4939 = 0.028953 n_p times p = 3298 times 0.028953 = 95.49, which is more than 10 n_p times p = 1641 times 0.028953 = 47.51, which is more than 10 (and the other two products are larger)

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0

Answer:

Detailed solution is given below in the attached image

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Stephen Curry makes 43.5% of his 3 point shots. In a typical season, Curry takes around 700 3 point shots. Assume Curry takes 70
Paladinen [302]

Answer:

a. Find the probability that Curry makes less than 300 3 point shots.

4 0
2 years ago
Three sisters want to.Buy a pda for their fauther for fauthers day. The least expensive pda in the sorr isn$360. Writenand slove
zzz [600]

Answer:

$120

Step-by-step explanation:

I would like to rewrite your question for others easy to understand:

<em>"Three sisters want to Buy a pda for their father for fathers' day. The least expensive pda in the store  is $360. Writen and slove an inequality to fund the least amout of money each girl would have ti contrubute if each contribute an equal amount" </em>

<em />

Let X is the the amount one girl contribute, we have 3 girls => 3X

The least expensive pda in the store  is $360, so the total contributed amount must be equal or smaller than the pda cost

<=> 3X  \leq 360

<=> X \leq 120

So the least amout of money each girl would have to contrubute is $120

5 0
3 years ago
Help me <br> Show all your work
Andreyy89
3x+2 (5x-1)=11
3x +10x -2=11
3x+10x=13
13x=13
X=1
4 0
3 years ago
Read 2 more answers
Question 7 of 10
andriy [413]

Answer:

C. n = 90; p = 0.8

Step-by-step explanation:

According to the Central Limit Theorem, the distribution of the sample means will be approximately normally distributed when the sample size, 'n', is equal to or larger than 30, and the shape of sample distribution of sample proportions with a population proportion, 'p' is normal IF n·p ≥ 10 and n·(1 - p) ≥ 10

Analyzing  the given options, we have;

A. n = 45, p = 0.8

∴ n·p = 45 × 0.8 = 36 > 10

n·(1 - p) = 45 × (1 - 0.8) = 9 < 10

Given that for n = 45, p = 0.8, n·(1 - p) = 9 < 10, a normal distribution can not be used to approximate the sampling distribution

B. n = 90, p = 0.9

∴ n·p = 90 × 0.9 = 81 > 10

n·(1 - p) = 90 × (1 - 0.9) = 9 < 10

Given that for n = 90, p = 0.9, n·(1 - p) = 9  < 10, a normal distribution can not be used to approximate the sampling distribution

C. n = 90, p = 0.8

∴ n·p = 90 × 0.8 = 72 > 10

n·(1 - p) = 90 × (1 - 0.8) = 18 > 10

Given that for n = 90, p = 0.9, n·(1 - p) = 18 > 10, a normal distribution can be used to approximate the sampling distribution

D. n = 45, p = 0.9

∴ n·p = 45 × 0.9 = 40.5 > 10

n·(1 - p) = 45 × (1 - 0.9) = 4.5 < 10

Given that for n = 45, p = 0.9, n·(1 - p) = 4.5 < 10, a normal distribution can not be used to approximate the sampling distribution

A sampling distribution Normal Curve

45 × (1 - 0.8) = 9

90 × (1 - 0.9) = 9

90 × (1 - 0.8) = 18

45 × (1 - 0.9) = 4.5

Now we will investigate the shape of the sampling distribution of sample means. When we were discussing the sampling distribution of sample proportions, we said that this distribution is approximately normal if np ≥ 10 and n(1 – p) ≥ 10. In other words

Therefore;

A normal curve can be used to approximate the sampling distribution of only option C. n = 90; p = 0.8

3 0
3 years ago
Select all expression that are equivalent to 64 2/3.
pav-90 [236]

Answer:

<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>D</u></em></h2>

Step-by-step explanation:

As,

{64}^{ \frac{2}{3} }  =  {(\sqrt[3]{64})}^{2}  =  \sqrt[3]{ {64}^{2} }

8 0
3 years ago
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