Answer:
A
Step-by-step explanation:
For the answer to the question above,
The mean value theorem states the if f is a continuous function on an interval [a,b], then there is a c in [a,b] such that:
<span>f ' (c) = [f(b) - f(a)] / (b - a) </span>
<span>
So [f(a) - f(b)] ( b - a ) = [sin(3pi/4) - sin(pi/4)]/pi </span>
= [sqrt(2)/2 - sqrt(2)/2]/pi = 0
So for some c in [pi/2, 3pi/2] we must have f ' (c) = 0
In general f ' (x) = (1/2) cos (x/2)
We ask ourselves for what values x in [pi/2, 3pi/2] does the above equation equal 0.
0 = (1/2) cos (x/2)
0 = cos (x/2)
x/2 = ..., -5pi/2, -3pi/2, -pi/2, pi/2, 3pi/2, 5pi/2,...
x = ..., -5pi, -3pi, -pi, pi. 3pi, 5pi, ....
and x = pi is the only solution in our interval.
So c = pi is a solution that satisfies the conclusion of the MVT
Answer:
i dont remember how to answer this so heres some info from the graph.
the y-intercept of the first equation is 8.
the y-intercept of the second equation is 18.
the equations cross at (10,4)
Okay so for the first one, letter A, it is a pentagon because it has 5 sides. It doesn't need to be all equal sides because it's not a equilateral pentagon.
For letter B, it does not because that shape does not have all equal sides (If it does then it will have the line marks.
For letter C, it is not a equilateral pentagon with at least one right angle because it isn't even a equilateral pentagon in the first place and a right angle is 90 degrees. I hope this helps!
Your answer would be D. 121.
The reason why this is your answer because Angle 15 is congruent to 3 (The same).
