PLeAsE hElP mEeEe

True [87]

Answer:

1. While Biology is the study of living things, living things themselves are made up of chemical composition. Our survival is dependant on the reactions taking place inside and outside the body. Hence, to understand living things, biologists needs a good understanding of chemistry.

2. 170 pm is the radius of a Carbon Atom.

3. The vast majority of the mass of an atom is concentrated in its nucleus

4. Protons are found in the nucleus of the atom. This is a tiny, dense region at the center of the atom. Protons have a positive electrical charge of one (+1) and a mass of 1 atomic mass unit (amu), which is about 1.67×10−27 kilograms.

5. Neutrons are located with protons in the nucleus; they too exchange mesons with protons and with each other to form the strong nuclear force, but they do not have to overcome the repulsion from Coulomb forces since neutrons are not charged.

7 0

3 years ago

Number of different amino acids that make up all proteins

klemol [59]

Answer:

List of the 20 Amino Acids

Amino Acid 3-Letter Abbreviation 1-Letter Abbreviation Class of Amino Acid (Side Chain) Hydrophobicity Index (100 being extremely hydrophobic, 0 being neutral, and -55 being hydrophilic) Structure pKa of COOH group pKa of NH3+ group pKa of R group Molecular Weight [g/mol] alpha helix beta sheet Reverse turn

Glycine Gly G Aliphatic, nonpolar Neutral (0 at pH = 2; 0 at pH = 7)

2.4 9.8 -- 75.07 0.43 0.58 1.77

Alanine Ala A Aliphatic, nonpolar Hydrophobic (47 at pH = 2; 41 at pH = 7)

2.4 9.9 -- 89.1 1.41 0.72 0.82

Valine Val V Aliphatic, nonpolar Very Hydrophobic (79 at pH = 2; 76 at pH = 7)

2.3 9.7 -- 117.15 0.90 1.87 0.41

Leucine Leu L Aliphatic, nonpolar Very Hydrophobic (100 at pH = 2; 97 at pH = 7)

2.3 9.7 -- 131.18 1.34 1.22 0.57

Isoleucine Ile I Aliphatic, nonpolar Very Hydrophobic (100 at pH = 2; 99 at pH = 7)

2.3 9.8 -- 131.18 1.09 1.67 0.47

Methionine Met M Hydroxyl or Sulfur-Containing, nonpolar Very Hydrophobic (74 at pH = 2; 74 at pH = 7)

2.1 9.3 -- 149.21 1.30 1.14 0.52

Serine Ser S Hydroxyl or Sulfur-Containing, polar Neutral (-7 at pH = 2; -5 at pH = 7)

2.2 9.2 -- 105.09 0.57 0.96 1.22

Cysteine Cys C Hydroxyl or Sulfur-Containing, polar Hydrophobic (52 at pH = 2; 49 at pH = 7)

1.9 10.7 8.4 121.16 0.66 2.40 0.54

Threonine Thr T Hydroxyl or Sulfur-Containing, polar Neutral (13 at pH = 2; 13 at pH = 7)

2.1 9.1 -- 119.12 0.76 1.17 0.96

Proline Pro P Cyclic Hydrophilic (-46 at pH = 2; -46 at pH = 7)

2.0 9.6 -- 115.13 0.34 0.31 1.32

Phenylalanine Phe F Aromatic Very Hydrophobic (92 at pH = 2; 100 at pH = 7)

2.2 9.3 -- 165.19 1.16 1.33 0.59

Tyrosine Tyr Y Aromatic Hydrophobic (49 at pH = 2; 63 at pH = 7)

2.2 9.2 10.5 181.19 0.74 1.45 0.76

Tryptophan Trp W Aromatic Very Hydrophobic (84 at pH = 2; 97 at pH = 7)

2.5 9.4 -- 204.25 1.02 1.35 0.65

Histidine His H Basic Hydrophilic at pH=2 (-42), Neutral at pH=7 (8)

1.8 9.3 6.0 155.16 1.05 0.80 0.81

Lysine Lys K Basic Hydrophilic (-37 at pH = 2; -23 at pH = 7)

2.2 9.1 10.5 146.188 1.23 0.69 1.07

Arginine Arg R Basic Hydrophilic (-26 at pH = 2; -14 at pH = 7)

1.8 9.0 12.5 174.2 1.21 0.84 0.90

Aspartate Asp D Acidic Neutral at pH=2 (-18), Hydrophilic at pH=7 (-55)

2.0 9.9 3.9 133.10 0.99 0.39 1.24

Glutamate Glu E Acidic Neutral at ph=2 (8), Hydrophilic at pH=7 (-31)

2.1 9.5 4.1 147.13 1.59 0.52 1.01

Asparagine Asn N Acidic, polar Hydrophilic (-41 at pH = 2; -28 at pH = 7)

2.1 8.7 -- 132.118 0.76 0.48 1.34

Glutamine Gln

8 0

4 years ago

Read the paragraphs and answer the question that follows.

Artemon [7]

We can infer of the two paragraphs that Geological movements are often hazardous when they happen quickly, and that the movement of plate boundaries does not always cause disaster.

The excerpt is telling us that "the <span>earthquakes caused a lot of damage, as well as dramatic changes to the local ecosystem", which is supporting the conclusion: "geological movements are often hazardous when they happen quickly."
But is also telling us that "</span>The slip caused several rock formations and structures to develop cracks. However there was no large-scale disaster or disruption.", which is supporting the conclusion: the movement of plate boundaries does not always cause disaster."

4 0

3 years ago

Read 2 more answers

Positive feedback

choli [55]

Answer:

B)

Explanation:

"Positive feedback encourages and intensifies a change in the body's physiological condition, driving it farther out if the normal range."

4 0

3 years ago

3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the

konstantin123 [22]

Answer and Explanation:

Available Data:

1 gr beets = 2,000 cal

NPP = GPP – Respiration = 120 grams/m2/day

NPP= Net primary productivity of a system

GPP= Gross productivity of the producers

Respiration loss 25% of NPP

Insolation energy is 800 calories/cm2/day

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day

8 0

3 years ago