Question

A copper contact is insulated from its support with one piece of mica 1⁄64 inch thick, two pieces of fiber that are each 1⁄8 inch thick, and 1⁄16 inch of pressboard. The copper is 3⁄4 inch thick, and the support is 7⁄8 inch thick. What is the total thickness of copper, insulation, and support?

Answer 1

Answer:

125/64=1(61/64) inch

Step-by-step explanation:

The complete thickness would be the sum of individual thickness in the array.

The cooper would be the upper layer with 3/4 inch thick, the support is the middle layer composed by three sublayers: 1/64 inch mica, 2 pieces of fiber of 1/8 inch each (2/4 inch both) and a pressboard with 1/16 inch thick. The bottom layer is the support with 7/8 inch thick.

The sum would be:

$Total_thickness=\frac{3}{4} +\frac{1}{64} +\frac{2}{8} +\frac{1}{16} +\frac{7}{8}inch=\frac{3(16)+1(1)+2(8)+1(4)+7(8)}{64}inch=\frac{125}{64}inch =(1+\frac{61}{64}) inch=1\frac{61}{64} inch$