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Y_Kistochka [10]
3 years ago
13

E is the midpoint of DF. IF DE = x + 5 and DF = 3x + 2, what is DF?

Mathematics
2 answers:
suter [353]3 years ago
8 0

Answer:

13

Step-by-step explanation:

If E is the midpoint, Then DE = FE

=> x+5 = 3x+2

=> 3x-x = 5-2

=> 2x = 3

=> x = 3/2

<u><em>Now DF:</em></u>

=> 3/2 + 5 + 3(3/2)+2

=> (3+10)/2 + (9+4)/2

=>  (13+13)/2

=> 26/2

=> 13

prisoha [69]3 years ago
6 0

Answer:

13

Step-by-step explanation:

x+5=3x+2

5=2x+2

3=2x

x=1.5

1.5+5=6.5

6.5 is half of DF, DF=13

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An account grows at an annual interest rate of r⁡​ ⁣, so it grows by a factor of x=1+r⁡​ ⁣⁣ ​⁡ each year. The function A(x)=800x
Paladinen [302]

Given:

Annual interest rate = r⁡​%

Growth factor : x = 1 + r⁡​

The below function gives the amount in the account after 4 years when the growth factor is x⁡​ ⁣⁣.

A(x)=800x^4+350x^3+500x^2+600x

To find:

The total amount in the account if the interest rate for the account is 3% each year and initial amount.

Solution:

Rate of interest = 3% = 0.03

Growth factor : x = 1 + ⁡0.03 = 1.03

We have,

A(x)=800x^4+350x^3+500x^2+600x

Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.

A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)

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A(1.03)=900.407048+382.45445+530.45+618

A(1.03)=2431.311498&#10;

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Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.

For initial amount the rate of interest is 0.

Growth factor : x = 1 + ⁡0 = 1

Substitute x=0 in the given function to find the initial amount.

A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)

A(1)=800+350+500+600

A(1)=2250

Therefore, 2250 was put into the account at the beginning.

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3 years ago
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Dmitriy789 [7]

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Here in this question, we need to know the quadratic equation whose graph was shown.

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The roots of the equation are the solution to the quadratic equation and can be seen from the graph at the point where the quadratic equation crosses the x-axis.

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Multiplying both will give us the quadratic equation we are looking for.

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<h3>You are correct. The answer is the second choice.</h3>

BC = JC by the single tickmarks shown

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The angles between these two pairs of sides, that you've marked in the second answer choice, are needed to use SAS (side angle side).

See the diagram below. In the diagram, angle BCD (green) is between segments BC and CD. Also, angle JCD (blue) is between JC and CD.

3 0
3 years ago
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