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2 years ago

What is the area of the figure

Mathematics

1 answer:

svp [43]2 years ago

6 0

Formula for the area of a triangle:

( Base X Height ) Divided by 2 or (B×H) ÷ 2

Formula for the area of a circle:

PI times the radius squared or PI × r^2

Area of the triangule part of this figure:

Base: 8ft. Height: 6ft

(8ft × 6ft) ÷ 2

48ft^2 ÷ 2

24ft^2

Since the circular part of the figure is a SEMICIRCLE, we are finding the area of a circle with the same radius but dividing it by 2 since thats just a half of a circle

Area of the semicricle:

Diameter: 10ft,

Therefore the radius is 5ft

(PI x 5ft^2) ÷ 2

39.2699081699 ft^2

39.27 ft^2

Now add these two areas together:

24ft^2 + 38.27ft^2 = 62.27ft^2

Hope it helps

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Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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$\mu$ population mean (variable of interest)

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Part a

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=\pm 1.64$

Part b

The distribution for the sample mean is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE = \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{9}}=1$

Part c

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And the margin of error is:

$ME= z_{\alpha/2} \frac{\sigma}{\sqrt{n}} = 1.64$

And then the confidence interval is be given by:

$200-1.64 = 198.36$

$200+1.64 = 201.64$

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2 years ago

What is the area of the figure​

What is the area of the figure