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Leokris [45]
3 years ago
15

A green rectangle tile and a yellow rectangular tile are similar. The green tile has a length of 24 centimeters and a perimeter

of 80 centimeters. The yellow tile has a length of 72 centimeters. What is the perimeter of the yellow tile?
Mathematics
1 answer:
sesenic [268]3 years ago
8 0
"The perimeter of yellow tile is 240 cm."

Green tile and yellow tile are similar.
Perimeter of green tile = 80 cm
length of green tile = 24 cm
length of yellow tile = 72 cm
perimeter of yellow tile = ?
now you see if you multiply the length of green tile with 3 you get the length of yellow tile;
24 x 3 = 72 cm
As given that both tiles are similar so, if you multiply the perimeter of green tile with 3, you will get the perimeter of yellow tile;
80 x 3 = 240 cm
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Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant
Alex787 [66]

Find the intercepts for both planes.

Plane 1, <em>x</em> + <em>y</em> + 2<em>z</em> = 2:

y=z=0\implies x=2\implies (2,0,0)

x=z=0\implies y=2\implies(0,2,0)

x=y=0\implies 2z=2\implies z=1\implies(0,0,1)

Plane 2, 4<em>x</em> + 4<em>y</em> + <em>z</em> = 8:

y=z=0\implies4x=8\implies x=2\implies(2,0,0)

x=z=0\implies4y=8\impliesy=2\implies(0,2,0)

x=y=0\implies z=8\implies(0,0,8)

Both planes share the same <em>x</em>- and <em>y</em>-intercepts, but the second plane's <em>z</em>-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (<em>x</em>, <em>y</em>)-plane where <em>z</em> = 0, we see the bounded region projects down to the triangle in the first quadrant with legs <em>x</em> = 0, <em>y</em> = 0, and <em>x</em> + <em>y</em> = 2, or <em>y</em> = 2 - <em>x</em>.

So the volume of the region is

\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx

=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx

=\displaystyle\int_0^2\left(7-7x+\frac74 x^2\right)\,\mathrm dx=\boxed{\frac{14}3}

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Answer:

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Step-by-step explanation:

7 0
3 years ago
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How to simplify -1.71.
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3 years ago
1-i need to mix 25% mineral spirits to the varnish i am using what ratio of spirit to varnish am i using? 2-if i use 240 ml of v
zhenek [66]

Answer:

(1) The required ratio of spirit to varnish is 1:3.

(2) You need 80 ml of mineral spirit.

(3) The ratio of tapestries' heights to width is 3:2.

Step-by-step explanation:

(1) If you need to mix 25% mineral spirit to the varnish, then the solution would contain 25% mineral spirit and 75% varnish.

So, \frac{spirit}{varnish}=\frac{25}{75}

                  =\frac{1}{3}

Thus, The required ratio of spirit to varnish is 1:3.

(2) If you use 240ml of varnish, then this quantity is 75% of the total solution or ration of varnish to the total solution will be 3:4.

Let x be the quantity of total solution.

Then, 240:x=3:4.

⇒\frac{240}{x}=\frac{3}{4}

⇒3x=240*4

⇒x=\frac{240*4}{3}

⇒x=320

That is, total solution is 320 ml.

Now, Spirit = Total solution - Varnish

⇒Spirit = 320ml-240ml

⇒Spirit = 80ml

Hence, if you use 240 ml of varnish, you need 80 ml of mineral spirit.

(3) Robison's tapestries all measure 1.5m long and 1m wide. First, we express dimensions in whole numbers by multiplying them by 10.

Then, dimensions are 15m long and 10m wide.

Now, Height : Width = 15:10

⇒\frac{Height}{Width} =\frac{15}{10}

⇒\frac{Height}{Width} =\frac{3}{2}

Hence, the ratio of tapestries' heights to width is 3:2.

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3 years ago
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garik1379 [7]
The answer is b). (0,0)
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