Website Math papa can help w that
Answer:
A = 38°
B = 50.32°
C = 91.68°
a = 8
b = 10
c = 12.77
Step-by-step explanation:
The first thing is to find the angle B, like this:
sin B = b * sin A / a = 10 * sin (38 °) / 8
sin B = 0.77
B = arc sin (0.77)
B = 50.32 °
For angle C, it would be:
C = 180 - 38 - 50.32
C = 91.68 °
Side c, we calculate it like this:
c = a * sin C / sin A = 8 * sin (91.68 °) / sin (38 °)
c = 12.77
Given : - Square ABCD with side 3. E and F as midpoints.
To find : - area of EBFD
Solution : - We have, area of square ABCD = 3 x 3 = 9 units.
Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF
arDAE = 1/2 x base x height
=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25
arDFC = 1/2 x base x height
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25
Thus, (ar) EBFD = arABCD - arDAE - arDCF
= 9 - 2.25 - 2.25
= 4.5 units.
Thus, area of quad EBFD is 4.5 units.
30 + 2x = 90
2x = 60
x = 30
Answer:
x = 30
I hope this helps you
Circumference =2.pi.r
60=2.3,14.r
r=30/3,14
Arc Length = 140/360.2.3,14.30/3,14
Arc Length =70/3
