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notsponge [240]
3 years ago
9

A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base

is 300 m and the minimum diameter, 500 m above the base, is 200 m. Find an equation describing the shape of the tower in the coordinates where the origin is at the center of the narrowest part of the tower. In particular, use coordinates where the origin is 500 m above the ground.
Mathematics
2 answers:
zaharov [31]3 years ago
5 0

Okay so the equation you need to use is (x2/a2)+(y2/b2)-(z2/c2)=1

So an equation describing the shape of the tower in the coordinates where the origin is at the center of the narrowest part of the tower would be:

<span>x^2 / 100^2 + y^2 / 100^2 – z^2 / 2 * 100^2 = 1</span>

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

SpyIntel [72]3 years ago
4 0
Hello,

as  the bases are circles,
equation is :

\dfrac{x^2}{a^2} + \dfrac{y^2}{a^2}- \dfrac{z^2}{c^2}=1\\\\&#10;if\ x=100,y=0,z=0\ then \  \dfrac{100^2}{a^2}=1\\\\&#10;a=100\\\\&#10;if\ x=150,y=0,z=-500\  then \\&#10; \dfrac{150^2}{100^2} + \dfrac{0^2}{100^2}- \dfrac{500^2}{c^2}=1\\\\&#10;c=100*\sqrt{2} \\\\&#10;\boxed{\dfrac{x^2}{100^2} + \dfrac{y^2}{100^2}- \dfrac{z^2}{2*100^2}=1}&#10;&#10;

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3 years ago
-Solve each equation. Example x+3=12 9+3=12
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7 0
3 years ago
A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and
goblinko [34]

Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

where;

F= force applied on the spring

x = the extension on the spring

k= the spring constant which varies in spring.

The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

Here the spring extension is 15 m

<u>In spring B</u>

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

<u>Compare</u>

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

=15m-12m=3m

5 0
3 years ago
Could someone please help me answer both questions!
Nady [450]

Answer:

1. m = 2n

2. m = 3n + 1

Step-by-step explanation:

1. 8 = 4 * 2; 10 = 5 * 2; 18 = 9 * 2....

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4/5 divided by 1/3 ??
DochEvi [55]

Answer:

2.4

Step-by-step explanation:

3 0
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