No two <em>intergers</em> can solve this problem. If you're not in Algebra II yet, the answer is probably "none."
Just look at the factor pairs of 25:
1 × 25
-1 × 25
5 × 5
-5 × -5
Clearly none of those can add up to 6.
If you want the more complex answer, I'll show you how here. If you don't understand why it doesn't work, that's okay. I just want you to see that there's not an actual answer to the problem.
a+b = 6
a = 6-b
ab = 25
(6-b)b = 25
6b -b² = 25
-b² + 6b = 25
b² -6b = -25
Factor by splitting the middle.
Half of -6 is -3, (-3)² = 9. Add this to each side.
b² -6b + 9 = -16
Factor the perfect square trinomial.
(b-3)² = -16
Take the square root of each side.
b-3 = 4i
b = 3+4i
a+b = 6
a+3+4i = 6
a= 3-4i
<em>(The "i" stands for an imaginary number, specifically, the square root of -1.)</em>
Answer:
2 weeks
Step-by-step explanation:
18 divided by 8 which is 2.25 just round it to the nearest tenth so it would be 2 weeks
Answer:
How do you find the sum of factors of a quadratic equation?
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C r = -2 - u s = -2 + u Two numbers r and s sum up to -4 exactly when the average of the two numbers is \frac{1}{2}*-4 = -2.
How do you solve a quadratic equation?
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
Step-by-step explanation:
Answer:
80
Step-by-step explanation:
2 times 10 is 20
8 times 10 is 80
40 times 10 is 400
60 times 10 is 600
Answer: then y should equal 1
Step-by-step explanation: because 4 is half of 8 and 1 is half of 2
