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Kruka [31]
3 years ago
6

I’m stuck please help

Mathematics
2 answers:
ratelena [41]3 years ago
5 0

the answer for this is 4q+10


weqwewe [10]3 years ago
4 0
Since there are 2 negatives in front of the 8, it becomes positive 8

-4q + 8q + 10

4q + 10

4q = -10

q = -10/4 or reduce it to -5/2
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the pressure, p. of a gas varies inversely with its volume, v. Pressure is measured in units of Pa. Suppose that a particular am
LekaFEV [45]

I think I know how to do it


Your equation is:

P₁V₁ = P₂V₂


You Know:

Initial:

P₁ = 84 Pa

V₁ = 336 L


New:

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V₂ = 216L


Plug this into the equation:

P₁V₁ = P₂V₂

(84 Pa)(336 L) = P₂(216 L)     Divide 216 on both sides

\frac{(84Pa)(336L)}{216L}=\frac{(P_{2})(216L)}{216L}

130.6666666 = P₂    

(if your doing significant figures, you have 2 sig figs)

130 Pa = P₂


6 0
3 years ago
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Answer:

-2

Step-by-step explanation:

Let's plug your functions f(x)=x^2-2x and g(x)=6x+4 into (f+g)(x)=0 and then solve your equation for x.

So (f+g)(x) means f(x)+g(x).

So (f+g)(x)=x^2+4x+4

Now we are solving (f+g)(x)=0 which means we are solve x^2+4x+4=0.

x^2+4x+4 is actually a perfect square and is equal to (x+2)^2.

So our equation is equivalent to solving (x+2)^2=0.

(x+2)^2=0 when x+2=0.

Subtracting 2 on both sides gives us x=-2.

7 0
3 years ago
Read 2 more answers
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AleksandrR [38]

Answer:

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nikklg [1K]

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