Question

the pressure, p. of a gas varies inversely with its volume, v. Pressure is measured in units of Pa. Suppose that a particular amount of gas is initially at a pressure of 84 Pa at a volume of 336L. If the volume is expanded to 216L. what will the new pressure be

Answer 1

I think I know how to do it

Your equation is:

P₁V₁ = P₂V₂

You Know:

Initial:

P₁ = 84 Pa

V₁ = 336 L

New:

P₂ = ?

V₂ = 216L

Plug this into the equation:

P₁V₁ = P₂V₂

(84 Pa)(336 L) = P₂(216 L)     Divide 216 on both sides

$\frac{(84Pa)(336L)}{216L}=\frac{(P_{2})(216L)}{216L}$

130.6666666 = P₂    

(if your doing significant figures, you have 2 sig figs)

130 Pa = P₂