Answer:
since there are 8 cards, and 2 say WIN, 6 of the 8 cards don't say WIN. You can express this as a ratio of 6:8 which equals 3:4, so the probability that neither says win is 75%.
Step-by-step explanation:
Step-by-step explanation:
On a frigid, foggy Christmas Eve in London, a shrewd, mean-spirited cheapskate named Ebenezer Scrooge works meticulously in his counting-house. Outside the office creaks a little sign reading "Scrooge and Marley"--Jacob Marley, Scrooge's business partner, has died seven years previous. Inside the office, Scrooge watches over his clerk, a poor diminutive man named Bob Cratchit. The smoldering ashes in the fireplace provide little heat even for Bob's tiny room. Despite the harsh weather Scrooge refuses to pay for another lump of coal to warm the office.
Please explain more your question
297/11 = 27
So we have 27 groups of 11 students. If there are 2 chaperones for every 11 students, then we can do:
27x2=54
There are 54 chaperones on the field trip.
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
