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2 years ago

8

Freeeeeeeeeee points I hope your get some

2 answers:

kramer2 years ago

4 0

Answer:

thanks

Step-by-step explanation:

Ber [7]2 years ago

3 0

Answer: :)

Step-by-step explanation:

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ANSWER ASAP ( Remember to pull out the GCF or you will get it wrong)

dimaraw [331]

A I believe please let me know

4 0

2 years ago

Read 2 more answers

What is the mean for this set of data?

oee [108]

The mean is 14

add all the numbers up and divide the sum by 6 because that’s how many numbers you’re adding together.

12+10+14+18+14+16
= 84

84/6 = 14

5 0

3 years ago

Prime factorization of 204

drek231 [11]

Prime factors are basically the smallest whole numbers that multipy to get that number so
204=2 times 102
102=2 times 51
51=3 times 17
prime factorization is 2 times2 times 3 times 17

8 0

3 years ago

Solve: 9-2x = 4x + 33

worty [1.4K]

Simplifying
4x+-9= 2x + 33
Reorder the terms:
-9+4x = -2x + 33
Reorder the terms:
-9 + 4x = 33 + -2x
Solving:
-9 + 4x = 33 + -2x
Answer: x = 7

6 0

3 years ago

An environmental engineer is tasked with determining whether a power plant cooling system is heating the water it uses more than

Tpy6a [65]

Answer:

1

The correct option is b

2

The correct option is h

Step-by-step explanation:

From the question we are told that

The sample size is n = 15

The difference in population proportion is $d = 6$

Generally the sample mean of the input temperature is

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{57.6 + 68.9 + \cdots +60.4 }{15}$

=> $\= x_1 = 62.57$

Generally the sample mean of the output temperature is

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{65.1 + 74.4 + \cdots +67.3 }{15}$

=> $\= x_2 = 55.97$

Generally the difference of the sample mean of the input temperature and that of the output temperature is

$\= d = \= x_1 - \= x_2$

=> $\= d = 62.57 -55.97$

=> $\= d = 6.6$

Generally the standard deviation is mathematically represented as

$s_d = \sqrt{\frac{\sum(d_1 - \= d )^2}{n} }$

=> $s_d = \sqrt{\frac{([57.6- 65.1]- 6.6)^2+ ([68.9 - 74.4]- 6.6)^2 + \cdots + ([60.4 - 67.3]- 6.6)^2 }{15} }$

=> $s_d = 1.732 [/texGenerally the test statistics is mathematically represented as [tex]t = \frac{ d - \= d }{ \frac{s_d}{\sqrt{n} } }$

=> $t = \frac{ 6-6.6 }{ \frac{1.732}{\sqrt{15} } }$

=> $t = 1.3417$

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 15 - 1$

=> $df = 14$

Generally the probability of t obtained from the t - distribution table at a degree of freedom of $df = 14$ is

$P(t >1.3417 ) = 0.10052569$

Generally the p-value is mathematically represented as

$p-value = 2 * P(t > 1.3417)$

=> $p-value = 2 * 0.10052569$

=> $p-value = 0.201$

From the values obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is

The cooling system changes the temperature of the water by 6 degrees.

8 0

3 years ago