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irina1246 [14]
2 years ago
13

Which ordered pair is a solution of the equation?

Mathematics
1 answer:
Leno4ka [110]2 years ago
6 0
Yes papa papa daddy daddy lol yeah bye yeah yeah bye
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Please Help! Will mark brainliest!
Wittaler [7]

Answer:

11

Step-by-step explanation:

Let a= times he hit 4 par

Let b = times he hit 5 par

a+b=18 => 4a+4b = 72

4a+5b=79

b=79-72=7

So a = 11

8 0
3 years ago
Read 2 more answers
You’re given three angle measurements of 30°, 70°, and 80°. How many triangles can you construct using these measurements?
Katyanochek1 [597]
Only one  cause it takes 180 degrees<span> to make a triangle so all you do is add it up</span>
6 0
3 years ago
Corey has 140 marbles. He gives 16 to his younger brother. He divides the rest equally into four bags. How many go in each bag?
madreJ [45]
31 marbles would go into each bag.
8 0
3 years ago
Which polynomial is a difference of two squares? x2 − 16 x2 + 16 x2 − 8 x2 + 8
mart [117]
Difference means subtract so we can reduce the choices right away to first and third choices. of the only the first is the difference of squares, namely x² - 4²
8 0
4 years ago
Find the indicated probability. round to three decimal places. a test consists of 10
Charra [1.4K]

To answer this problem, we use the binomial distribution formula for probability:

P (x) = [n! / (n-x)! x!] p^x q^(n-x)

Where,

n = the total number of test questions = 10

<span>x = the total number of test questions to pass =   >6</span>

p = probability of success = 0.5

q = probability of failure = 0.5

Given the formula, let us calculate for the probabilities that the student will get at least 6 correct questions by guessing.

P (6) = [10! / (4)! 6!] (0.5)^6 0.5^(4) = 0.205078

P (7) = [10! / (3)! 7!] (0.5)^7 0.5^(3) = 0.117188

P (8) = [10! / (2)! 8!] (0.5)^8 0.5^(2) = 0.043945

P (9) = [10! / (1)! 9!] (0.5)^9 0.5^(1) = 0.009766

P (10) = [10! / (0)! 10!] (0.5)^10 0.5^(0) = 0.000977

Total Probability = 0.376953 = 0.38 = 38%

<span>There is a 38% chance the student will pass.</span>

7 0
3 years ago
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