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3 years ago

Solve for the inequality ?

Mathematics

1 answer:

iren2701 [21]3 years ago

4 0

$|x|\leq3\\
x\leq 3 \wedge x\geq-3\\
x\in[-3,3]$

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9. A computer chip manufacturer knows that 72% of the chips produced are defective.

adoni [48]

The probability that exactly 800 chips are acceptable is less than 0.000001

<h3>How to determine the probability?</h3>

The given parameters are:

Sample, n = 3000
Percentage acceptable, p = 72%
Acceptable chips, x = 800

The binomial probability is represented as:

$P(x) = ^nC_x * p^x * (1- p)^{n - x}$

So, we have:

$P(300) = ^{3000}C_{800} * (72\%)^{800} * (1- 72\%)^{3000 - 800}$

The data values are large.

So, we use a statistical calculator to evaluate the expression

Using the calculator, we have:

P(300) < 0.000001

Hence, the probability that exactly 800 chips are acceptable is very small i.e. less than 0.000001

Read more about probability at:

brainly.com/question/25870256

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2 years ago

If a city has 159 murders a year what dors that averahe in a week

aliya0001 [1]

There are 52 weeks in one year. If we divide 159 by 52 we get 3.05. Therefore, there would be an average of 3-4 murders per week.

6 0

3 years ago

If (x+2) is a factor of x^3-6x^2+kx+10, k=

Alja [10]

If a binomial $(x-a)$ is a factor of a polynomial, then $a$ is a root of this polynomial.

$(x+2)=(x-(-2)) \Rightarrow a=-2\\\\
(-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\
-8-24-2k+10=0\\
-2k=22\\\
\boxed{k=-11}
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2 years ago

Pls only do this if yk it because i’m giving correct answer brainliest! :))

Leno4ka [110]

Answer:

$x=2+\frac{1}{2}\sqrt[]{21}$

$x=2-\frac{1}{2}\sqrt{{21}$

Step-by-step explanation:

$4x^2-16x-26=-21$

Add 21 on both sides.

$4x^2-16x-26+21=-21+21$

$4x^2-16x-5=0$

a=4

b=-16

c=-5

$x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}$

$x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)} }{2(4)}$

$x=\frac{16\frac{+}{}\sqrt[]{256+80} }{8}$

$x=\frac{16\frac{+}{}\sqrt[]{336} }{8}$

$x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21} }{8}$

$x=\frac{16\frac{+}{}2*2\sqrt[]{21} }{8}$

$x=\frac{16\frac{+}{}4\sqrt[]{21} }{8}$

---------------------------------------------------------------------------

$x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}$

$x=2+\frac{1}{2}\sqrt[]{21}$

---------------------------------------------------------------------------

$x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}$

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2 years ago

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I need help with this question I'm not sure what the answer is

Tpy6a [65]

Answer:15/17

Step-by-step explanation: cos = adjacent/hypotenuse

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3 years ago