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4 years ago

PLZ HELP MEEEEEEEEEEE!!!!!!!

Mathematics

2 answers:

krok68 [10]4 years ago

5 0

Answer:

x=27

Step-by-step explanation:

Nana76 [90]4 years ago

4 0

Answer:

x=-1

Step-by-step explanation:

consider x-14 as a variable and you will get 3(x-14)=39 and then you simplify to get 3x-42=39 and 3x will equal -3 so x = -1

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The graph of h(x) is shown. Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which

fgiga [73]

Answer:

x-intercept

The point at which the curve crosses the x-axis, so when y = 0.

From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)

y-intercept

The point at which the curve crosses the y-axis, so when x = 0.

From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)

Asymptote

A line which the curve gets infinitely close to, but never touches.

From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5

(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).

5 0

2 years ago

Read 2 more answers

Please help no links!!

Phoenix [80]

add my discord Big_Man #8293

8 0

3 years ago

Hey guys its my first time using this app, i need help with this question! b) 3/x + 4/x+2

Rasek [7]

Answer:

7/x+2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I need help solving for x: log x = 2.46 - 1.12 * log y

Mariulka [41]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\\\\\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)
\\\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{log cancellation rule}\\\\
-----------------------------\\\\$

$\bf log(x)=2.46-1.12log(y)\iff log_{10}(x)=2.46-1.12log_{10}(y)
\\\\\\
log_{10}(x)=2.46-log_{10}(y^{1.12})\implies log_{10}(x)+log_{10}(y^{1.12})=2.46
\\\\\\
log_{10}(x\cdot y^{1.12})=2.46\implies 10^{\cfrac{}{}log_{10}(x\cdot y^{1.12})}=10^{2.46}
\\\\\\
xy^{1.12}=10^{2.46}\implies \boxed{x=\cfrac{10^{2.46}}{y^{1.12}}}$

8 0

4 years ago

The price of an item has been reduced by 60% . The original price was $45 . What is the price of the item now?

Leokris [45]

Answer:

twenty-seven dollars

Step-by-step explanation:

0.6×$45=$27

8 0

3 years ago