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4 years ago

Solve for f 3(6−f)−4=3f−4

Mathematics

1 answer:

Neko [114]4 years ago

4 0

1. Simplify the left side

-3f+14=3f-4

2. Combine like terms by moving all the terms containing f to the left of the equation

-6+14=-4

3. Move all the terms not containing f to the right side of the equation

-6f=-18

4. Divide each side by 6

f=3

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Write a real-world problem that can be represented by the given equation. Explain what your variable represents. 2X + 6 = 3X + 4

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Answer:

2,340

Step-by-step explanation:

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3 years ago

Find the surface area of the hexagonal prism

arsen [322]

Answer:

$4,636.8 \: {in}^{2}$

Step-by-step explanation:

Surface area of the hexagonal prism

= Area of base * Height

= 6*Area of one triangle *height

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3 years ago

Solve each equation for y. 3x + 2 =6y

Strike441 [17]

Answer:

1/2x + 1/3 = y

Step-by-step explanation:

3x + 2 =6y

Divide each side by 6

3x/6 + 2/6 = 6y/6

Simplify

1/2x + 1/3 = y

6 0

3 years ago

) At a certain instant of time, a cube has side length 2 inches and its volume is increasing at a rate of 0.5 inches cubed per h

Phantasy [73]

Answer:

1 inches per cube

As required.

Step-by-step explanation:

Solution:

Given:

Volume = l3

dV / dt = 3 l2dl / dt

dv / dt = 0.5 inches cubed / hour

Surface area = 6 l2

Differentiate with respect to t: s = 6 l2

We get:

ds / dt = 12 l dl / dt

and dv / dt = = 0.5 inches cubed / hour

we know that:

dv / dt = 20 = 3 l2dl / dt

0.5 = 3 l2 (dl / dv)(dv / dt)

0.5 = 3l2 dl / dt

0.5 / 3l2 = dl / dt

Put 0.5 / 3l2 = dl / dt in eq ds / dt = 12 l dl / dt

ds / dt = 12 l (0.5 / 3l2)

= 4(0.5) / l

= 2 / 2 inches pr cube [ l = 2 inches per cube]

= 1 inches per cube

As required.

3 0

3 years ago

if A and B together can do a piece of work in 10 days and B along can do it in 15 days, how many part of the work does A complet

anzhelika [568]

Answer:

1/5

Step-by-step explanation:

Well work can be defined as: $work = rate \ *\ time$

where rate=amount of work that can be done in one unit of time

let a = rate of work A does in a day

let b = rate of work B does in a day

this means that: $10a + 10b=1$ where work=1 and it just means the entire job has been completed.

Since b can do it alone in 15 days, this means that: $15b=1$

If we divide by 15 here, we get the equation: $b=\frac{1}{15}$

We can now use this definition to substitute it into the first equation we made.

$10a + 10(\frac{1}{15}) = 1$

Multiply the 10 and 1/15

$10a+\frac{2}{3}=1$

subtract 2/3 from both sides

$10a=\frac{1}{3}$

Now divide both sides by 10

$a=\frac{1}{30}$

Now multiply this by 6, since we a represents the amount of work that can be done in a day, we want to find how many parts of the work can be done by a in 6 days

$6a=\frac{6}{30}$

Now divide both the numerator and denominator by 6

$a=\frac{1}{5}$

8 0

2 years ago