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Alik [6]
3 years ago
7

Parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'.

Mathematics
2 answers:
azamat3 years ago
6 0

we know that

The scale factor is equal to

Scale\ Factor=\frac{F'G'}{FG}

we have

F'G'=8\ units\\FG=2\ units

substitute

Scale\ Factor=\frac{8}{2}

Scale\ Factor=4

therefore

<u>the answer is</u>

4

aalyn [17]3 years ago
5 0

Answer: 4

Step-by-step explanation:

From the given picture, To find scale factor between figures, find two corresponding sides and write the ratio of the two sides.

The value of y is same through the distance of F to G.

So, FG= change in x coordinates

FG=|-2-(-4)|=|-2|=2 units

Similarly , F'G'=|3-(-5)|=|8|=8 units

Let k be the scale factor of the dilation.

The scale factor of the dilation is given by :-

k=\frac{F'G'}{FG}\\\Rightarrow\ k=\frac{8}{2}=4

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The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
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142.2 meters.  

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We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

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\text{Total surface area of cuboid}=2(lb+bh+hl), where,

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\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

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Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

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3 years ago
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