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Alik [6]
3 years ago
7

Parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'.

Mathematics
2 answers:
azamat3 years ago
6 0

we know that

The scale factor is equal to

Scale\ Factor=\frac{F'G'}{FG}

we have

F'G'=8\ units\\FG=2\ units

substitute

Scale\ Factor=\frac{8}{2}

Scale\ Factor=4

therefore

<u>the answer is</u>

4

aalyn [17]3 years ago
5 0

Answer: 4

Step-by-step explanation:

From the given picture, To find scale factor between figures, find two corresponding sides and write the ratio of the two sides.

The value of y is same through the distance of F to G.

So, FG= change in x coordinates

FG=|-2-(-4)|=|-2|=2 units

Similarly , F'G'=|3-(-5)|=|8|=8 units

Let k be the scale factor of the dilation.

The scale factor of the dilation is given by :-

k=\frac{F'G'}{FG}\\\Rightarrow\ k=\frac{8}{2}=4

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Answer:

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Step-by-step explanation:

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3 years ago
PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
mash [69]

Answer:

(-6,9,-3)

Step-by-step explanation:

-3x -y +z=6

-3x-y+3z =0

x-3z =3

Multiply the second equation by -1

-1 *(-3x-y+3z) =0*-1

3x +y -3z =0

Add this to the first equation

-3x -y +z=6

3x +y -3z =0

----------------------

0 + 0 + -2z = 6

Divide by -2

-2z/-2 = 6/-2

z = 6/-2

z=-3


Take the third equation to find x

x-3z=3

x-3(-3) = 3

x+9=3

Subtract 9 from each side

x+9-9 =3-9

x=-6

Now we need to find y

3x +y -3z =0

3(-6) +y -3(-3) =0

-18 +y +9=0

-9+y =0

Add 9 to each side

-9+9+y = 0+9

y=9

(-6,9,-3)

3 0
3 years ago
Read 2 more answers
Anyone here good at algebra? if so PLEASE HELP MEH ;-;
vovangra [49]
I’ll tell y’all 4 if did
7 0
3 years ago
15 points!!! GEOMETRY help please!!<br> Questions attached!
dolphi86 [110]
3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o

Answer:\ \boxed{47^o}

4.
Look at the picture.

Use Pythagorean theorem:

x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8

Used:\ (a+b)^2=a^2+2ab+b^2

Answer:\ \boxed{4.8\ units}

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}

We have: OP:\ y=-\dfrac{3}{2}x+b

Now, we must find the slope of the line perpendicular to the line OP.
We know:

k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1

therefore

-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}

So. We have the answer! :)

Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}

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3 years ago
What is an equation in slope-intercept form for the line that passes through the points (1, -3) and (3,1)
DedPeter [7]
The last one y=2x-5 if you plug the points into the x and y values you can see this equation works for both points.
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2 years ago
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