All categories

3 years ago

Can someone help me with this 1-6

Biology

1 answer:

Elena L [17]3 years ago

6 0

Answer:

1. sperm cell

2.testicles

3.egg

4.ovary

5.fertilization

6.fertilized egg = foetus

Explanation:

You might be interested in

In a savanna, gazelles, wildebeests, and warthogs eat grasses. Lions and cheetahs eat gazelles and wildebeests. Lions and wild d

Assoli18 [71]

Answer:

what is the question ?....

Explanation:

5 0

2 years ago

What is Biotechnology ?

dimulka [17.4K]

Answer:

The exploitation of biological processes for industrial and other purposes, especially the genetic manipulation of microorganisms for the production of antibiotics, hormones, etc.

Explanation:

5 0

2 years ago

Read 2 more answers

The gene for red-green colorblindness is located on

weeeeeb [17]

Mother. red-green color blindedness is maternally inherited

8 0

2 years ago

Two hybrid striped zebrafish mate and produce offspring. Stripes is dominant over no-stripes. What is the genotype ratio and phe

denis23 [38]

Stripes, and are heterozygous for both GloYFP and gol. (Fig. 3). The progeny phenotype ratios are approximately 3:1 yellow:gray and 1:1 striped: nonstriped ...
16 pages·618 KB

4 0

2 years ago

The number of cells in an average-sized adult human is on the order of 10^14 cells. Use this information, and the estimate that

KengaRu [80]

IF:
Number of cells: $C = 10^{14}$
DNA lenght: $D = 2m = 12.42 * 10^{-4} mi$
Distance from Earth to Sun: $ES=93000000 mi = 9.3* 10^{7}mi$

Then:
a) Over how many miles would the total DNA from the average human stretch?
The answer is product of multiplication of the number of cells (C) and the DNA length (D):
Total DNA: $T = C*D$
⇒ $T = 10^{14}*12.42* 10^{-4} mi$
⇒ $T = 12.42* 10^{14-4} mi$
⇒ $T = 12.42* 10^{10} mi$
The total DNA from the average human will stretch $12.42* 10^{10} mi$

b) How many times would the total DNA from the average human stretch from Earth to the Sun and back?
The answer is concluded from the ratio of the total DNA length (T) and the twice (because of stretch to the Sun and back, thus, two directions) of distance from Earth to the Sun (ES) and :
Ratio: $R= \frac{T}{2*ES}$
⇒ $R = \frac{12.42* 10^{10}mi }{2*(9.3* 10^{7}mi)}$
⇒ $R = \frac{12.42* 10^{10}}{18.6*10^{7}}$
⇒ $R = 0.6677* 10^{10-7}$
 ⇒ $R = 0.6677* 10^{3}$
 ⇒ [tex]R = 667.7
Thus, 667,7 times will the total DNA from the average human stretch from Earth to the Sun and back.

6 0

3 years ago