S+m+l=28
4s+2m+l=58
6s+5m+4l=135
Eliminate the variable l from the first 2 equations
s+m+l=28
-4s-2m-l=-58
-3s-m=-30
Elminiate the variable l from the last 2 equations
6s+5m+4l=135
-16s-8m-4l=-232
-10s-3m=-97
Now solve for s and m using the 2 equations without l
-3s-m=-30
-10s-3m=-97
9s+3m=90
-10s-3m=-97
-s=-7
s=7
Then plug in s into one of the equations without l
-3(7)-m=-30
-21-m=-30
-m=-9
m=9
Now plus in s and m into one of the original 3 equations
(7)+(9)+l=28
16+l=28
l=12
Final answer:
Small=$7
Medium=$9
Large=$12
I know it only asks for large but I wanted to show you how to find them all for future reference. :)
Answer: x=
−2
3
y+20
Step-by-step explanation
240=12x+8y
Step 1: Flip the equation.
12x+8y=240
Step 2: Add -8y to both sides.
12x+8y+−8y=240+−8y
12x=−8y+240
Step 3: Divide both sides by 12.
12x
12
=
−8y+240
12
x=
−2
3
y+20
Answer:
x=
−2
3
y
Answer:
Step-by-step explanation:
we have
Adds 16 both sides
(-4)^-6*(-4)^7 = (-4)^1 = -4
answer a. -4
