Answer:
1) you use any parallel lines or rectangles we can double the triangle to get the area and then divide by 2 as we know the length is 92.5yards and we know the width is 53.5 yards.
We would x these by each other and then divide by 2.
We have the width 53 1/2 yards wide and convert this to decimal if we want.
= 53.5 yards.
We then can count the yards for the length = 90 hash marks = 90 yards+ 2.5
= 92.5yards.
We square then add to find the hypotenuse diagonal line but it is an estimate as the lines inscribed subtends into the corner and it becomes a little larger as bottom line is used. Diagonal is found after by doing a reverse equation on the area.
53.5 x 92.5 then divide by 2 = 4948.75/2 = 2474.375
then 2474.375/ 26.75 = 92.5
This proves the line is isosceles and also find the height of the triangle.
But only as an estimate as the actual line distends
Last answer is B and W are equal measures this is because we do not see a right angle and if we bisected the triangle from the goal line to the left side we would prove the midpoint goal line is actually equal and makes lines of play isosceles where two sides are the same at point B and W.
So the answer is 1 yard as B runs the length of the goal back to a position of diagonal run.
The diagonal length is 92.5 yards
Step-by-step explanation:
Answer:
The rug should be 15 ft wide and 28 ft long.
Step-by-step explanation:
I have attached a figure that represents the situation.
The the rug is 
by 
, the width of the strip of floor is 
.
We are told that Cynthia can only afford 420 square feet of carpeting; therefore, it must be that
<em>(this says the area of the rug must be 420 square feet)</em>
From the figure we see that
Therefore,
We expand this equation and get:
using the quadratic equation we get two solutions:
since the second solution, namely 
, is larger than one of the dimensions of the room (is greater than 19 ft) it cannot be the width of the strip; therefore, we take 
to be our solution.
Now we find the dimensions of the rug:
The rug is 15 ft wide and 28 ft long.
Hi there!
The answer is C. m
The name of a line is always a lower-case letter (e.g. m, k or any other letter from the alphabet).
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
