Answer: 17/52
Step-by-step explanation:
There are 52 total cards in a standard deck.
The number of diamonds in a deck of cards is 13 and there are 4 jacks in a deck of cards.
So the propabibilty of Pat picking a diamond is 13/52 and the probability of Pat picking a jack is 4/52. Now you have to add the two probabilities together.
You do not remove any digits because Pat put the card back into the deck, he didn't take it away. So we do not take away from the total
13 + 4 = 17
You do not need to change the denominator cause 52 is the same.
So 17/52 is the probability of Pat picking a diamond or a jack
I hope this helped!
Answer:
The answer to the problem is 21.1
It seems okay to me (if that what your asking) I don't know this subject very well ut the part your working on " I'm familiar with ?" Don't be surprised if I was wrong buuuuut it does look okay to me "(the answer)".
Answer:
x=2
Step-by-step explanation:
We know AC = BC since this is an isosceles triangle
6 = 2x+2
Subtract 2 from each side
6-2 =2x+2-2
4 =2x
Divide each side by 2
4/2 =2x/2
2=x
Answer:
-$13.5
Step-by-step explanation:
Let x be a random variable of a count of player gain.
- We are told that if the die shows 3, the player wins $45.
- there is a charge of $9 to play the game
If he wins, he gains; 45 - 9 = $36
If he looses, he has a net gain which is a loss = -$9
Thus, the x-values are; (36, -9)
Probability of getting a 3 which is a win is P(X) = 1/6 since there are 6 numbers on the dice and probability of getting any other number is P(X) = 5/6
Thus;
E(X) = Σ(x•P(X)) = (1/6)(36) + (5/6)(-9)
E(X) = (1/6)(36 - (5 × 9))
E(X) = (1/6)(36 - 45)
E(X) = -9/6 = -3/2
E(X) = -3/2
This represents -3/2 of $9 = -(3/2) × 9 = - 27/2 = -$13.5