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UNO [17]
3 years ago
9

A slice is made perpendicular to the base of a right rectangular prism as shown.

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
The cross section is just a rectangle. So to work out the area, multiply the length of the base together by the height.
This is 22 x 12 = 264cm²
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7 less than the product of a number n and 1/6 is no more than 98​
VikaD [51]

Answer:

1/6, 1/6, 630

Step-by-step explanation:

1/6*n-7≤98

1/6*n≤98+7

1/6*n≤105

n≤105*6

n≤630

7 0
3 years ago
Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3
LekaFEV [45]

Answer:

(a)\ \sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128} = 8 \sqrt{2}

Step-by-step explanation:

Required

Simplify

(a)\ \sqrt{20}

Express 20 as 4 * 5

\sqrt{20}=\sqrt{4 * 5}

Split

\sqrt{20}=\sqrt{4} * \sqrt{5}

This gives:

\sqrt{20}=2 * \sqrt{5}

\sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300

Express as 100 * 3

\sqrt{300} = \sqrt{100} * \sqrt{3}

This gives:

\sqrt{300} = 10 * \sqrt{3}

\sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128}

Express as 64 * 2

\sqrt{128} = \sqrt{64*2}

Split

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0
2 years ago
The tables for f(x) and g(x) are shown below.
Vinvika [58]

Answer:

  16

Step-by-step explanation:

(f - g)(5) = f(5) -g(5)

From the tables, ...

  f(5) = 29

  g(5) = 13

Your desired function is ...

  f(5) -g(5) = 29 -13 = 16

8 0
3 years ago
Find the surface area and volume of the following figures.
Oduvanchick [21]

White figure Area = 128\pi

White surface area = appro. 301

Yellow area = 320\pi

Yellow Surface area = approx. 653

Area found with = 2πrh+2πr2

Surface Area found with = 2πrh+2πr2

You need to memorize them for tests

Hope that helped!!! k

4 0
3 years ago
Read 2 more answers
Help help help help please business
Margaret [11]

Answer:

x = 35°

Step-by-step explanation:

These are corresponding angles. When a transversal crosses 2 parallel lines, 4 angles are created at each intersection, and each pair of corresponding angles between those are congruent.

These angles are congruent, so you can set them equal to each other:

2x+20=3x-15

Then, just solve for x:

20=x-15\\35=x\\x=35

You can check that by plugging it back into both:

2x+20=3x-15\\2(35)+20=3(35)-15\\70+20=105-15\\90=90

3 0
2 years ago
Read 2 more answers
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