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DIA [1.3K]
4 years ago
9

PLZ HELP!!! What is the solution to the system of equations?

Mathematics
2 answers:
coldgirl [10]4 years ago
3 0

Answer:

there is no solution

Step-by-step explanation:

plbecause there is no sso

Elden [556K]4 years ago
3 0

There is no solution

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Time/Distance/Speed
NemiM [27]
Time = distance / speed 
         = 95/ 105  =  0.905 hours or about  54.3 minutes or 54 minutes 17 seconds
6 0
3 years ago
In the diagram, line a is the perpendicular bisector of km. what is the length of km?
sleet_krkn [62]

Answer:

80

Step-by-step explanation:

From the given diagram;

KN = NM

9x - 5 = 7x + 7

9x - 7x = 7 + 5

2x = 12

x = 12/2

x = 6

Since KM= 2KL

KM = 2(6x+4)

KM = 12x + 8

KM = 12(6)+8

KM = 72+8

KM = 80

Hence the length of KM is 80

6 0
3 years ago
Jerry bought a rectangular kitchen table. The table is 1.6 m wide and 2.3 m long. What is the area of the top of the table?
sweet [91]
13.8 sq. m because 1.6 x 2.3= 13.8
8 0
3 years ago
Read 2 more answers
Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 116. Assume t
PSYCHO15rus [73]

Answer:

(a) 93.19%

(b) 267.3

Step-by-step explanation:

The population mean and standard deviation are given as 502 and 116 respectively.

Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.

(a) The percent of the SAT verbal scores are less than 675 can be calculated as:

P(X

Thus, the required percentage is 93.19%

(b)

The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:

P(X>575)=P(\frac{x-502}{116}>\frac{575-502}{116}\\P(X>575)=P(Z>\frac{575-502}{116})\\P(X>575)=P(Z>0.6293)\\P(X>575)=0.2673

So,

Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.

8 0
3 years ago
Nick received an 82.5% on his math test. How many questions did he get right if there was a total of 40
Burka [1]
33.

Using division if you do 33/40 you get 82.5%
5 0
3 years ago
Read 2 more answers
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