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laiz [17]
3 years ago
12

You work for a lender that requires a 15% down payment and uses the standard debt-to-income ratio to determine a person's eligib

ility for a home loan. Of the following, choose the person that you would rate the highest on their eligibility for a home loan.
Person A
Person B
Person C
Person D
home value
$95,000
$107,000
$120,000
$128,000
income
$46,000
$53,000
$58,000
$60,000
savings
$20,000
$13,910
$18,000
$19,200
recurring debt
$310
$198
$265
$400

a.
Person A
b.
Person B
c.
Person C
d.
Person D
Mathematics
2 answers:
vova2212 [387]3 years ago
4 0
The answer to this would be b
Volgvan3 years ago
3 0

Answer: The answer is C. Person C


Step-by-step explanation:


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A) make U subject of the formula E= m/2g(v^2-u^2)
ollegr [7]

Answer:

u = v2−2Egm−−−−−−−√

Step-by-step explanation:

2Eg = 2g (M2g(V2−U2)

2Eg = m(V2 - U2)

2Eg - mV2 - mU2

mU2 = mV2 - 2Eg

mU2m=mV2−2Egm

U2 = mV2−2Egm

= mV2m−2Egm

U2 = V2 - 2Egm

U = V2−2Egm−−−−−−−−√

7 0
3 years ago
How many terms are in the following expression: 7x + 3y – 5 + 2x + 11
zepelin [54]
There are 3 terms. Because if you simplify it, 7x and 2x would be 9x.. and -5+11 would be 6 so there would be (9x+3y+6) left. so 3 terms
6 0
3 years ago
Read 2 more answers
Simplify the expression 4x^3 2x^3
kotykmax [81]

Answer:

Step-by-step explanation:

2 3x6

the 3 is an exponet so supost to be smaller

5 0
3 years ago
Read 2 more answers
Please help!!!!
valentina_108 [34]
ANSWER

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t  + 6}{ t + 2}
where,
t \ne - 2



EXPLANATION

We want to simplify the rational expression

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }


We can observe that the numerator of the given rational expression is a quadratic trinomial and the denominator is a difference of two squares



We need to split the middle term in the numerator and rewrite the denominator as a difference of two squares to obtain,




\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{{t}^{2}  + 6t - 2t - 12}{ {t}^{2}  -  {2}^{2} }



We now factor to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t (t+ 6) - 2(t  + 6)}{ (t  -  2)(t + 2)}


This implies that,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t - 2) (t  + 6)}{ (t  -  2)(t + 2)}


We now cancel out common factors to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t  + 6)}{ (t + 2)}


The restriction is that, the denominator cannot be zero.

Thus

t + 2 \ne0


This implies that,

t  \ne - 2
6 0
4 years ago
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The curve y= (1-x)/(x-3) is concave up when:
Diano4ka-milaya [45]
Use quotient rule to find y"
y" = [-(x-3)-(1-x)]/(x-3)^2 = 2/(x-3)^2
y" = -4/(x-3)^3
 -4/(x-3)^3 > 0
 (x-3)^3 < 0
 x-3 < 0
 x< 3

hope this help
7 0
4 years ago
Read 2 more answers
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