Answer:
4x^2 + 8x + 4
4(x^2 + 2x + 1) - remove GCF of 4
4(x + 1)(x + 1) - factor
4(x + 1)^2 - collect like terms
Step-by-step explanation:
Then also expand it out by distributing:
21x^3 + 35x²
Form 1:
21x^3 + 35x² - unfactored
Form 2:
7x²(3x + 5) - factored with GCF of 7x² brought to the front
Update:
You could also multiply two binomials and make a quadratic.
Example:
(7x + 2)(3x + 5)
7x(3x + 5) + 2(3x + 5)
= 21x² + 35x + 6x + 10
= 21x² + 41x + 10
Um I think the answer is 3
Using pseudocode:
printArray(arr[], integers)
DECLARE integers
integers = SizeOf(arr)
FOR i = 1 to integers // loop from 1 to the number of elements in arr[]
print(i)
print('')
i = i + 1
ENDFOR
END
(49)(58) = 2,842
49
x58
------
2,842
Answer:
Step-by-step explanation:
S56=56/2[2(-8)+(56-1)7]
S56=10332
