Area of a rectangle=length x width
You have two rectangles:
First rectangle (the biggest):
length=9 yd
width=12 yd-6 yd=6 yd
Area of the biggest rectangle=(9 yd)(6 yd)=54 yd²
Second rectangle (the smallest)
length=6 yd
width=3 yd
Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²
Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.
area of the ballroom=54 yd² +18 yd²=72 yd²
Answer:
Step-by-step explanation:
Simplifying
6 = 1 + -2n + 5
Reorder the terms:
6 = 1 + 5 + -2n
Combine like terms: 1 + 5 = 6
6 = 6 + -2n
Add '-6' to each side of the equation.
6 + -6 = 6 + -6 + -2n
Combine like terms: 6 + -6 = 0
0 = 6 + -6 + -2n
Combine like terms: 6 + -6 = 0
0 = 0 + -2n
0 = -2n
Solving
0 = -2n
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '2n' to each side of the equation.
0 + 2n = -2n + 2n
Remove the zero:
2n = -2n + 2n
Combine like terms: -2n + 2n = 0
2n = 0
Divide each side by '2'.
n = 0
Simplifying
n = 0
Answer:
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Step-by-step explanation:
Answer:
64
Step-by-step explanation:
surface area of the cube =96
suppose one side of the cube = a
volume of the cube(V) =?
surface area = 6a^2
6a^2=96
a
^2
=96/6
a^2=16
a = 4
SO
V=
a^
3
V=64.
brainliest plz :'D
Answer:
x = 2,−6
Step-by-step explanation:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero
