You want to write this equation in the form (x+...)(x+...) (maybe with a minus sign). To do this, find numbers that, when multiplied, give 16, and when added give -10.
What whole numbers give 16?
1*16 and -1*-16
2*8 and -2*-8
4*4 and -4*-4
Which of these solutions, when changed into a sum, give -10?
Try them one by one and find it is:
-2-8 = -10.
So (x-2)(x-8) is the factorization!
This is really a bit of trial and error, but since most of the time the assignments deals with whole numbers, there aren't that many possibilities.
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