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3 years ago

10

The school council voted on their two candidates to become their student council president. The number of votes for candidate on

e was 523. The number of votes for candidate two was 412. About what percent of the votes were for candidate one?

2 answers:

vivado [14]3 years ago

7 0

the answer is 55.9% hope this helps

noname [10]3 years ago

7 0

M clap the sound of my heart

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therefore:
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2 years ago

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DochEvi [55]

Answer:

(-2,3)

Step-by-step explanation:

Step 1. Isolate x for 3x + 5y = 9

3x + 5y - 5y = 9 - 5y

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Step 2. Simplify

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2 years ago

WILL GIVE BRAINLIEST‼️‼️ If the mean of the following frequency distribution is 24; determine the value of p.

liq [111]

<h2>Answer- P=<u>18</u></h2>

Step-by-step explanation:

Greetings !

Firstly, find the class-midpoints (X) to solve for the mean.

Thus, mid points of each classes are

$5.15.25.35.45$

Solve, for <em>p</em><em> </em>using mean grouped data formula

$\frac{5(3) + 15(4) + 25(p) + 35(3) + 45(2)}{3 + 4 + p + 3 + 2} = 24$

multiply each values add them and solve for <em>p</em><em>.</em>

<em> $\frac{15 + 60 + 25p + 105 + 90}{12 + p} = 24$ </em>

make a cross multiplication

$270 + 25p = 24(12 + p) \\ 270 + 25p = 288 + 24p$

subtract 270 from both sides

$270 + 25p - 270 = 288 + 24p - 270 \\ 25p = 24p + 18$

subtract <em>24</em><em>p</em><em> </em>from both sides

$25p - 24p = 24p + 18 - 24p \\ p = 18$

Also refer the attached image for further details

Hope it helps!

5 0

2 years ago