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Romashka [77]
3 years ago
7

Help PLEASE 8 minutes left to submit

Mathematics
2 answers:
Karolina [17]3 years ago
8 0
You have the correct answer selected for this quiz!
disa [49]3 years ago
7 0
It’s the one you’ve already selected
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There are 100 people in a wedding house, including children, men and women, and there are 100 pappadas to give with Sadya Te.
olga nikolaevna [1]

Answer:

Two possible sets of answers.

5 men, 11 women and 42 children, or

10 men, 2 women and 88 children

Selamat Sadhya!

Step-by-step explanation:

M = number of men

W = number of women

100-M-W = number of children

Total number of pappadas

5M+3W+(100-M-W)/2 = 100

Solve for W

W = (100-9M)/5 .......................(1)

Examine equation (1).

In order to have W as a whole number, M must be multiple of 5

Therefore M = 5 or 10

If M = 5, W = (100-45)/5 = 11 and children = 100-5-11 =  84

If M = 10, W = (100-90)/5 = 2 and children = 100-10-2 = 88

8 0
3 years ago
PLEASE CAN SOMEBODY HELP PLEASE I AM BEGGING YOU PLEASE
rusak2 [61]
(3,-1)? i believe that's what it would be
5 0
3 years ago
Read 2 more answers
Factor the trinomial by using the factor X method 3n-8n+4
Alex73 [517]
3n² - 8n + 4
3n² - 6n - 2n + 4
(3n - 2)(n - 2)
7 0
3 years ago
PLEASE HELP!! 100 POINTS!! BRAINLIEST!! What is the GCF of the terms in the numerator and denominator? Rewrite the expression by
saul85 [17]

Answer:

2(2x-1)/x(x-4)

Step-by-step explanation:

4x^2-14x+6/x^3-7x^2+12x

2(2x^2-7x+3)/x(x^2-7x+12)

2(2x^2-6x-x+3)/x(x^2-4x-3x+12)

2(x-3)(2x-1)/x(x-4)(x-3)

6 0
3 years ago
A hollow toy, with the dimensions shown in the figure, is to be stuffed with rigid foam. What is the maximum amount of foam that
Fudgin [204]

Option B: 67.02 cubic inches

<h2>Given that:</h2>

The diagram consists of two parts:

  • First a cone on the top with 12 inches height and 4 inches diameter.
  • Second a semi sphere with diameter of 4 inches.

<h2>Calculations:</h2>

The amount of foams that can be stuffed with foam is total volume of both the containers.

Volume of the given cone of 12 inches height and 4 inches diameter can be given as:

\dfrac{1}{3} \times \pi \times 2^2 \times 12\\= 50.265 \: \rm inch ^3

Volume of the semi sphere of 4 inches diameter can be given as:

\dfrac{2}{3} \pi \times 2^3\\= 16.755 \: \rm inch^3

Thus total volume is 50.265 + 16.755 = 67.02 cubic inches.

Thus option B : 67.02 cubic inches is the needed volume.

Learn more here:

brainly.com/question/1315822

7 0
2 years ago
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