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S_A_V [24]
3 years ago
13

Which expression uses the greatest common factor and the distributive property to rewrite the sum 75 + 45?

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0
<span>75 + 45

First let's find the greatest common factor.
75: 1, 3, 5, 15, 25, 75
45: 1, 3, 5, 9, 15, 45
Their GCF is 15.

To get 75, you multiply 15 by 5.
To get 45, you multiply 15 by 3.

Therefore, 15(5 + 3) = 75 + 45.

</span><span>B. 15(5 + 3)
</span>
leonid [27]3 years ago
3 0


15(5 + 3) = 75 + 45.

B. 15(5 + 3)

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Answer:

The correct price is 10.01

Step-by-step explanation:

The manager multiplied the price by 43%, instead of noticing the words "mark up", which means the price increased by 43 percent and the cost is multiplied by 143/100!

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In the Ardmore Hotel, 20 percent of the guests (the historical percentage) pay by American Express credit card. (a) What is the
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Answer:

(a) The expected number of guests until the next one pays by American Express credit card is 4.

(b) The probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of guests until the next one pays by American Express credit card

The probability that a guest paying by American Express credit card is, <em>p</em> = 0.20.

The random variable <em>X</em> follows a Geometric distribution since it is defined as the number of trials before the first success.

The probability mass function of <em>X</em> is:

P(X=x)=(1-p)^{x}p;\ x=0,1,2,3...,\ 0

(a)

The expected value of a Geometric distribution is:

E(X)=\frac{1-p}{p}

Compute the expected number of guests until the next one pays by American Express credit card as follows:

E(X)=\frac{1-p}{p}

         =\frac{1-0.20}{0.20}

         =4

Thus, the expected number of guests until the next one pays by American Express credit card is 4.

(b)

Compute the probability that the first guest to use an American Express is within the first 10 to checkout as follows:

P(X=10)=(1-0.20)^{10}\times0.20

                 =0.1073741824\times 0.20\\=0.02147483648\\\approx0.0215

Thus, the probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.

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Answer:19/20

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I hope this is good enough:

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