Answer: 0.345
Step-by-step explanation:
Given : The incomes of families in Newport Harbor are normally distributed with Mean :
and Standard deviation : 
Samples size : n=4
Let x be the random variable that represents the incomes of families in Newport Harbor.
The z-statistic :-

For x= $800,000

By using the standard normal distribution table , we have
The probability that the average income of these 4 families exceeds $800,000 :-

Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345
Answer:
5/6=10/12. 2/4=6/12. 5/12
5/12. 2/4. 5/6
Answer:
11 0ver 54
Step-by-step explanation:
-8-3=-5. there . thats the answer.